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Romashka [77]
3 years ago
10

PLEASE TRY TO HELP !

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

the photo is a little blurry I cannot answer the question unfortunately sorry

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The perimeter of a rectangle is 4040 yards. what are the dimensions of the rectangle with maximum area?
Ivanshal [37]
Let x be the length and y be the width2x + 2y = 40x + y = 20change that into y = mx + b formy= 20 – x
Area =xy = x (20-x) = 20x - x^2Area=-x^2+20xcomplete the square:Area=-(x^2 – 20x + 100) +100=-(x - 10)^2 + 100This is an calculation of a parabola that opens downward with vertex at (10,100), which means maximum area of 100 happens when x, the length=10)Dimensions of the rectangle with maximum area? 10 yds. by 10 yds., a square.
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Dominique works in sales and gets paid $275 per week plus commission. This week he received a total pay of $5075. If his total s
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3 years ago
Find the missing probability.<br><br> P(A)=13/20,P(A∩B)=13/25,P(B|A)=?
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3 years ago
In one year a dog’s weight increased from 64 to 80. By what percentage did the dogs weight increase?
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3 0
2 years ago
27.) Find the sum of the length of line segments EF and CD
Lelechka [254]

Answer:

5√10

Step-by-step explanation:

The distance between two points A(x_1,y_1) and B(x_2,y_2) on the coordinate plane is given by:

|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }

From the image attached the coordinates of the points are E(-1, -1), F(8, -4), C(-7, -4) and D(-1, 2).

Hence the lengths of the line segment EF and CD are:

|EF|=\sqrt{(8-(-1))^2+(-4-(-1))^2} =\sqrt{90}=3\sqrt{10} \\\\CD=\sqrt{(-1-(-7))^2+(-2-(-4))^2}=\sqrt{40}  =2\sqrt{10} \\\\Therefore:\\\\|EF|+|CD|=3\sqrt{10} +2\sqrt{10} =5\sqrt{10}

6 0
3 years ago
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