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jeka94
3 years ago
8

Use the divergence theorem to calculate the outward flux of f=r|r|f=r|r| where r=⟨x,y,z⟩r=⟨x,y,z⟩ across ss: the hemisphere z=16

−x2−y2‾‾‾‾‾‾‾‾‾‾‾‾√z=16−x2−y2 and the disk x2+y2≤16x2+y2≤16 in the xyxy-plane.
Mathematics
1 answer:
yuradex [85]3 years ago
7 0

With \mathbf f=\mathbf r (?) you have divergence

\nabla\cdot\mathbf f=\dfrac{\partial x}{\partial x}+\dfrac{\partial y}{\partial y}+\dfrac{\partial z}{\partial z}=3

Then by the divergence theorem, the flux is

\displaystyle\iint_S\mathbf f\cdot\mathrm d\mathbf S=3\iiint_R\mathrm dV

where R denotes the interior of the region with boundary S.

Convert to spherical coordinates to set up the volume integral as

\displaystyle3\int_{\varphi=0}^{\varphi=\pi/2}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=0}^{\rho=4}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

=\displaystyle6\pi\left(\int_0^4\rho^2\,\mathrm d\rho\right)\left(\int_0^{\pi/2}\sin\varphi\,\mathrm d\varphi\right)

=128\pi

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