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finlep [7]
3 years ago
12

Consider a game in which a player rolls a number cube to determine the number of points earned. If a player rolls a number great

er than or equal to 4, the number of the roll is added to the total points. Any other roll is deducted from the player’s total. What is the expected value of the points earned on a single roll in this game?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0
The probability of rolling any specific number is 1/6. The expected number of points is found from:
E(points) = (1/6 * -1) + (1/6 * -2) + (1/6 * -3) + (1/6 * 4) + (1/6 * 5) + (1/6 * 6)
             = 9/6 = 1.5 points
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5 0
4 years ago
What is the 17th term in the arithmetic sequence in which a6 is 101 and a9 is 83
monitta

Answer:

The 17th term in arithmetic sequence is 68

Step-by-step explanation:

The general formula of arithmetic sequence is:

aₙ = a₁ + (n – 1)d.

We are given a₆ = 101 and a₉ = 83 and we need to find a₁₇

To find the term a₁₇ we should know a₁ and d. So we would find both

a₆ = a₁ +(6-1)d

101 = a₁ +(5)d

101 = a₁ +5d     eq(1)

and

a₉ = a₁ +(9-1)d    

83 = a₁ + 8d       eq(2)

Subtracting eq(2) from eq(1)

101 = a₁ +5d

83 = a₁ + 8d

-       -     -

__________

18 = -3d

=> d = 18/-3

=> d = -6

Putting value of d in eq(1)

101 = a₁ + 5d

101 = a₁ + 5(-3)

101 = a₁ -15

=> a₁ = 101+15

=> a₁ = 116

Now finding a₁₇:

aₙ = a₁ + (n – 1)d.

a₁₇ = 116 +(17-1)(-3)

a₁₇ = 116+(16)(-3)

a₁₇ = 116 - 48

a₁₇ = 68

So, the 17th term in arithmetic sequence is 68

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3 years ago
The general form of a quadratic is_______
goblinko [34]
Option c is correct make as a brainlist and thank me
6 0
3 years ago
Read 2 more answers
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