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finlep [7]
3 years ago
12

Consider a game in which a player rolls a number cube to determine the number of points earned. If a player rolls a number great

er than or equal to 4, the number of the roll is added to the total points. Any other roll is deducted from the player’s total. What is the expected value of the points earned on a single roll in this game?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0
The probability of rolling any specific number is 1/6. The expected number of points is found from:
E(points) = (1/6 * -1) + (1/6 * -2) + (1/6 * -3) + (1/6 * 4) + (1/6 * 5) + (1/6 * 6)
             = 9/6 = 1.5 points
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Really struggling with this, can someone please help me out and give me a brief explanation? Id seriously appreciate it.
Bogdan [553]

Answer:

314 m²

Step-by-step explanation:

the surface area of a sphere (As) is

As = 4×pi×r²

our radius r (half of the diameter) here is 5m.

As = 4×3.14×5² = 4×3.14×25 = 100×3.14 = 314 m²

8 0
2 years ago
Lines a and b in the figure above are parallel. What is the value of p?
elena-s [515]
It will be c- 20:
4q and 2(q+30) have to equal the same therefore q=30 which makes both these equations equal.
3p + 4q then have to equal 180 as they are on a straight line so you know q=30 so 4x30=120 so 180-120=60
Then 60/3=20 and that is your answer.
Hope this helps :)
7 0
3 years ago
Read 2 more answers
Solve 2x-5=7<br><br><br>Pls tell me
velikii [3]

Answer: if solving for x....

x= 6

Step-by-step explanation:

2x-5=7

2x-5+5=7+5

2x-5+5=7+5

2x/2= 12/2

x= 6

7 0
2 years ago
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The radius of a circle is 15 inches. A chord is drawn 4 inches from the center of the circle. How long is the chord?
Alex73 [517]

Let X represent the length of the chord.

By using Pythagoras' Theorem:

4^2 + (X/2)^2 = 15^2

(X^2)/4 = 209

X^2 = 836

X = 28.91

6 0
3 years ago
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
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