Answer:
The Taylor series of f(x) around the point a, can be written as:

Here we have:
f(x) = 4*cos(x)
a = 7*pi
then, let's calculate each part:
f(a) = 4*cos(7*pi) = -4
df/dx = -4*sin(x)
(df/dx)(a) = -4*sin(7*pi) = 0
(d^2f)/(dx^2) = -4*cos(x)
(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4
Here we already can see two things:
the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.
so we only will work with the even powers of the series:
f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....
So we can write it as:
f(x) = ∑fₙ
Such that the n-th term can written as:

Answer:
1. 8x2 - 7x + 4x3 - 2-3x2 + 9x - 4 = 16+2x
Step-by-step explanation:
1. Multiply all the multiplication problems (should look like this --> 16-7x+12-2-6+9x-4)
2. Calculate the sum or difference (should end up looking like this --> 16-7x+9x) and then into this (16 +2x)
Bringing us to the answer → <u>16 + 2x!</u>
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Answer:
This is the answer of your question. ☺☺
Step-by-step explanation:
1 because because power is 0
Answer:
-12 × -28
=336.
<h2>Hope it helps you.</h2>
Answer:
Speedy, Chloe, Annie, Pima, Piper