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zloy xaker [14]
3 years ago
6

What's the answer to this ?? Need help

Mathematics
2 answers:
UkoKoshka [18]3 years ago
7 0
3 x 4 = 12 so .3 x 4 would be 1.2


Veseljchak [2.6K]3 years ago
5 0
It goes by 3s so I think its 1.2
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Gina opened a bank account with $40. She plans to add $20 per week to the account and not make any withdrawals. After how many w
ZanzabumX [31]

Answer:

After 33 weeks.

Step-by-step explanation:

Let w be number of weeks.

We have been given that Gina opened a bank account with $40. She plans to add $20 per week to the account and not make any withdrawals. So the balance after w weeks will be 20w+40.

To figure out number of weeks Gina will have exactly $700 in her account, we will equate the balance after w weeks to 700.

20w+40=700

Let us subtract 40 from both sides of equation.

20w+40-40=700-40

20w=660

Upon Dividing both sides of our equation by 20 we will get,

\frac{20w}{20}=\frac{660}{20}

w=\frac{660}{20}

w=33

Therefore, after 33 weeks Gina will have exactly $700 in her account, excluding interest.

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4 years ago
I NEED HELP PLEASEEE ILL GIVE YOU MAX POINTS!!!
Lorico [155]
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2. 148.24
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3 0
3 years ago
amortization for house costs 35,000.00 at 6.5% interest for 10 years and payments of 400.00 were paid for 36 months what is the
UNO [17]

Answer:

$26,640.22

Step-by-step explanation:

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2 years ago
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Hi there! I haven't done math in a while but I do well and I hope this helps. First, we get our radius from our area, which is about 4 inches. From there, I used the volume formula and got the answer closest to C, or 267.95. Thanks, good luck :)

8 0
3 years ago
Find the first term and the common ratio <br>third term =6 and seventh term= 96​
mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: a_n= a_1r^{n-1}

We are given: third term = 6 i,e

a_3=a_1r(3-1)\\6=a_1r^2----eq(1)

Seventh term = 96

a_7=a_1r(7-1)\\96=a_1r^6----eq(2)

Dividing eq(2) and eq(3)

\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}

So, Common Ratio r = 2

Finding First term using eq(1)

a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}

So, First term a₁ = 3/2 and common ratio r = 2

6 0
3 years ago
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