$\lim_{x \to a} \frac{a-x}{\sqrt{x} -\sqrt{a} } \\ =-\lim_{x \to a} \frac{x-a}{\sqrt{x} -\sqrt{a} } \\=-\lim_{x \to a} \frac{(\sqrt{x} -\sqrt{a})(\sqrt{x} +\sqrt{a})}{\sqrt{x} -\sqrt{a} } \\=- \lim_{x \to a} \sqrt{x} +\sqrt{a}\\=-2\sqrt{a}$

6 0

2 years ago

Write an expression and then show the steps to solve the expression. Round to nearest hundredth. Explain what your solution mean

Semenov [28]

Answer:

see below

Step-by-step explanation:

Write an expression:

x + 1 = 1.011

solve the expression:

subtract 1 on left n right of the = sign

x + 1 - 1 = 1.011 - 1

x = 0.011

Round to nearest hundredth

x = 0.01

The solution is solving an algebra equation with the ans rounded to the hundredth.

4 0

3 years ago

Help pls!!! <br> If a1 = 6 and an<br> 2an-1 then find the value of a4.

Alenkinab [10]

24? I am not entirely sure but I think a4=24

Reason: if a1 equals 6 then I would like to think you would multiply 6 by 4 to get the value of a4 (I haven’t done this type of math in a while)

3 0

2 years ago