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3 years ago

What's the answer to this ?? Need help

Mathematics

2 answers:

UkoKoshka [18]3 years ago

7 0

3 x 4 = 12 so .3 x 4 would be 1.2

Veseljchak [2.6K]3 years ago

5 0

It goes by 3s so I think its 1.2

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Gina opened a bank account with $40. She plans to add $20 per week to the account and not make any withdrawals. After how many w

ZanzabumX [31]

Answer:

After 33 weeks.

Step-by-step explanation:

Let w be number of weeks.

We have been given that Gina opened a bank account with $40. She plans to add $20 per week to the account and not make any withdrawals. So the balance after w weeks will be 20w+40.

To figure out number of weeks Gina will have exactly $700 in her account, we will equate the balance after w weeks to 700.

$20w+40=700$

Let us subtract 40 from both sides of equation.

$20w+40-40=700-40$

$20w=660$

Upon Dividing both sides of our equation by 20 we will get,

$\frac{20w}{20}=\frac{660}{20}$

$w=\frac{660}{20}$

$w=33$

Therefore, after 33 weeks Gina will have exactly $700 in her account, excluding interest.

6 0

4 years ago

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Lorico [155]

1. 0.54 or 27/50
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3 years ago

amortization for house costs 35,000.00 at 6.5% interest for 10 years and payments of 400.00 were paid for 36 months what is the

UNO [17]

Answer:

$26,640.22

Step-by-step explanation:

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2 years ago

PLEASE HELP!!!

Eduardwww [97]

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3 years ago

Find the first term and the common ratio <br>third term =6 and seventh term= 96

mamaluj [8]

Answer:

First term a₁ = 3/2 and common ratio r = 2

Step-by-step explanation:

We need to find the first term and common ratio while we are given third term = 6 and seventh term = 96

Since common ratio is required so, the sequence is geometric sequence

The formula used is: $a_n= a_1r^{n-1}$

We are given: third term = 6 i,e

$a_3=a_1r(3-1)\\6=a_1r^2----eq(1)$

Seventh term = 96

$a_7=a_1r(7-1)\\96=a_1r^6----eq(2)$

Dividing eq(2) and eq(3)

$\frac{96}{6}=\frac{a_1r^6}{a1r2}\\16=\frac{r^6}{r^2}\\16=r^{6-2}\\=> r^4=16\\Taking \ fourth \ root\\ r=2,-2,2i,-2i\\ \ We \ will \ consider \ only \ positive \ value \ of \ r \ i.e \ \textbf{ r= 2}$

So, Common Ratio r = 2

Finding First term using eq(1)

$a_3=a_1r^2\\6=a_1(2)^2\\6=a_1(4)\\a_1= \frac{6}{4}\\a_1= \frac{3}{2}$

So, First term a₁ = 3/2 and common ratio r = 2

6 0

3 years ago