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grin007 [14]
3 years ago
11

Please can you help me! z-² as a fraction

Mathematics
1 answer:
Oksanka [162]3 years ago
5 0
\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{  n}}}\implies \cfrac{1}{a^{-{{  n}}}}\\\\
-------------------------------\\\\
z^{-2}\implies \cfrac{1}{z^2}
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Answer:

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Step-by-step explanation:

Given

p(x,y) = (6,0)

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Required

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In p(x,y) = (6,0), x = 6 and y = 0.

This gives:

a*6 + b*0 = 12

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Divide by 6

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In q(x,y) = (3,2). x = 3 and y = 2.

This gives:

a*3 + b*2 = 12

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