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Kazeer [188]
3 years ago
7

Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?

Mathematics
2 answers:
galina1969 [7]3 years ago
8 0
A). because the roots are shown. The roots of this quadratic function would be x=2, and x=-2
leonid [27]3 years ago
4 0

Answer:

A. h(x) = -4(x − 2)(x + 2)

Step-by-step explanation:

It's easiest to obtain roots from the factorize form

h(x) = -4(x − 2)(x + 2) = 0

x = 2, -2

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4 years ago
What is the result when the number 15 is decreased by 6%?
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Read 2 more answers
the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?
miss Akunina [59]
The equation of a circle in standard form is

(x - h)^2 + (y - k)^2 = r^2

where (h, k) is the center of the circle, and r is the radius if the circle.

We need to find the radius and center of the circle.
We are given a diameter, so to find the center, we need the midpoint of the diameter.

M = ((-6 + 6)/2, (6 + (-2))/2) = (0, 2)
The center is (0, 2).

To find the radius, we find the length of the given diameter and divided by 2.

d = \sqrt{(-6 - 6)^2 + (6 - (-2))^2)}

d = \sqrt{144 + 64}

d = \sqrt{208}

r = \dfrac{d}{2} = \dfrac{\sqrt{208}}{2} = \dfrac{\sqrt{208}}{\sqrt{4}} = \sqrt{52}

(x - 0)^2 + (y - 2)^2 = (\sqrt{52})^2

x^2 + (y - 2)^2 = 52
7 0
3 years ago
CAN SOMEONE PLS ANSWER THIS ILL REALLY APPREICIATE IT
GrogVix [38]
The answer would be -2! :)
3 0
3 years ago
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