<span>-1/4y(2y^3 - 8)
= -1/2 y^4 + 2 y</span>
Given:
A line passes through the two points (3,5) and (-1,1).
To find:
The equation of the line in fully reduced point-slope form.
Solution:
If a line passes through two points, then the point slope form of the line is
The line passes through the two points (3,5) and (-1,1). So, the point slope form of the line is
Therefore, the point slope form of the line in fully reduced form is , here 1 is the slope of the line.
Answer:
x= - 8
Step-by-step explanation:
multiply both sides by 4 to get rid of the fractions. you should then get:
2x-4x=x+24
then get all the x terms to one side by subtracting by x on each side:
2x-4x-x=24
then simplify:
-3x=24
divide by -3 on each side:
x= - 8
Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
Answer:
m = -5
Step-by-step explanation:
Step 1 :
Pulling out like terms/ factors
Add 5 to both sides of the equation :
-m = 5
Multiply both sides of the equation by (-1) : m = -5
<em><u>Hope this helps.</u></em>
