Answer:
First statement: 10 road workers take 5 days to complete a work, working 2 hours a day.
Let us calculate how many days 2 workers will need, if they were to work at the same pace (i.e. each working 2 hours a day). The workforce is now decreased to 2 divided by 10 = 1/5 (i.e. one-fifth).
Therefore proportionately, the time will increase to 5 days divided by 1/5, (i.e. 5 / (1/5) = 25 days.
We now know that 2 workers will need 25 days to finish the work, if they work for 2 hors a day.
Now the question is what will happen if the two people work 5 hours per day, instead of 2 hours per day?
The labor they put in has increased to 5 divided by 2 = 2.5 (i.e. 2 and half times).
Consequently, the time needed to finish the work will decrease to 25 divided by 2.5 (i.e. ( 25 / 2.5 ) = 10. days.
The answer : 10 Days.
Answer:
son's present age = 30
father's present age=60
Step-by-step explanation:
his son's present age = x years
his father's present age = 2x years
before 20 years his son's age=(x-20) years
before 20 years father's age=(2x-20) years4(x-20)=(2x-20)
4x-80=2x-20
4x-2x=80-20
2x=60
x=30
“huh” is the interjection!
Answer:
-3
Step-by-step explanation:
We want (n/p)(1). We can obtain this by finding n(1) and p(1) and then dividing as indicated:
p(1) = 3(1) - 2 = 1
n(1) = 2(1) - 5 = -3
Then (n/p) (1) = -3/1, or just -3
D = V • t ... displacement = velocity • time
d = [(s – 4) ⁄ (s² – 9s + 20)] • [(s – 5) ⁄ 4] ... rearrange terms
d = (s – 4) • (s – 5) ⁄ [4(s² – 9s + 20)] ... factor denominator
d = (s – 4) • (s – 5) ⁄ [4(s – 4) • (s – 5)]
d = ¼ mile
