Ethan has already jarred 4 liters of jam and will jar an additional 6 liters of jam every day.
2 answers:
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13. The equation of the given function is
14. The equation of the cotangent function is
Step-by-step explanation:
Let us revise the transformation of the trigonometric function:
y = a f[b(x + c)] + d, where
- Amplitude is a
- f represents the trigonometry function
- Period is 2π/b
- Phase shift is c (positive is to the left)
- Vertical shift is d
13.
∵ y = a sin( ), where a is the amplitude
and T is the wave in seconds
∵ The amplitude is 4
∴ a = 4
∵ The period is 4π
∴ T = 4π
From the rules above
∵ The period is 2π/b
∴ T =
∴ 4π =
- By using cross multiplication
∴ 4π(b) = 2π
- Divide both sides by 4π
∴ b =
∵ The phase shift is
∵ c is the phase shift
∴ c =
∵ The vertical shift is -2
∵ d is the vertical shift
∴ d = -2
Now substitutes the values of a, b, c and d in the form of the equation below
∵ y = a sin[b(t + c)] + d
∴
You can write it as
The equation of the given function is
14.
y = cot[b(t + c)] + d
∵ The period = π
∵ The period is 2π/b
- Equate π by 2π/b to find b
∴ π =
- By using cross multiplication
∴ π(b) = 2π
- Divide both sides by π
∴ b = 2
∵ The phase shift is
∵ c is the phase shift
∴ c =
∵ The vertical shift is 2
∵ d is the vertical shift
∴ d = 2
Now substitutes the values of b, c and d in the form of the equation below
∵ y = cot[b(t + c)] + d
∴
The equation of the cotangent function is
Learn more:
You can learn more about trigonometry function in brainly.com/question/3568205
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Answer:
1/16
Step-by-step explanation:
This question involves two distinct genes; one coding for seed shape and the other for cotyledon color. The alleles for round seeds (R) and yellow cotyledons (Y) are dominant over the alleles for wrinkled seed (r) and green cotyledon (y) respectively.
In a cross between a truebreeding (i.e. same alleles for both genes) pea having round seeds and yellow cotyledon (RRYY) and a truebreeding pea having wrinkled seeds and green cotyledon (rryy), the F1 offsprings will all possess a heterozygous round seed and yellow cotyledon (RrYy).
The F1 offsprings (RrYy) will produce the following gametes: RY, Ry, rY, and ry. Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced in a ratio 9:3:3:1.
According to the question, 3/16 of the F2 offsprings will possess round seeds and green cotyledons, however, only 1 of them will be truebreeding i.e. RRyy. Hence, 1/16 of the F2 offsprings will be truebreeding for round seeds and green cotyledons.
