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mrs_skeptik [129]
3 years ago
5

When matter changes from a solid to liquid or from liquid to gas, what kind of change takes place?

Chemistry
1 answer:
nataly862011 [7]3 years ago
6 0

Answer :-

Physical change

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A helium nucleus is formed from hydrogen nuclei. What nuclear change has occured? a.) beta decay b.) none c.) alpha decay d.) nu
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3 years ago
Part a cyclohexane has a freezing point of 6.50 ∘c and a kf of 20.0 ∘c/m. What is the freezing point of a solution made by disso
Andrei [34K]

The mathematical expression for the depression in freezing point is given as:

\Delta T_{f}= k_{f}m

where, \Delta T_{f} = depression in freezing point

k_{f} = molal depression constant    (20.0 ^{o}Ckg/mole)

m = molality

Molality is defined as the ratio of number of moles of solute to the kg of the solvent

Number of moles  =\frac{given mass in g}{molar mass}

given mass  of biphenyl solute = 0.925 g

Molar mass of biphenyl  = 154.21 g/mol

Put the values,

number of moles of biphenyl =\frac{0.925 g}{154.21 g/mol}

= 0.0059 mole

Molality =\frac{number of moles of biphenyl solute}{mass of the solvent in kg}

Mass of cyclohexane solvent  = 25.0 g

Convert g into kg: 1 kg = 1000 g

Thus, mass of cyclohexane  = \frac{25.0}{1000}

= 0.025 kg

Now, put the values in the formula of molality:

Molality =\frac{0.0059 mole}{0.025 kg}

= 0.236 mole/kg or 0.236 m.

Calculate the depression in freezing point:

\Delta T_{f}= 20.0^{o}C kg/mole\times 0.236 mole/kg

= 4.72 ^{o}C

Now, \Delta T_{f} = T_{solvent} - T_{solution}

4.72 ^{o}C = 6.50^{o}C - T_{solution}

T_{solution} = 6.50^{o}C- 4.72 ^{o}C

= 1.78^{o}C

Hence, freezing point of the solution is 1.78^{o}C.



4 0
3 years ago
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(50 POINTS AND BRAINLYEST PLEASE)
nexus9112 [7]
I’m pretty sure that the answer is current. Hope this helps
6 0
4 years ago
How do you write the formula for potassium hydroxide
makvit [3.9K]

KOH that or H3C-CH2-OH

7 0
3 years ago
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