Answer: Sorry i can't help, but good luck!
Explanation:❤️❤️❤️❤️ try hard!
When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed via SN₂ mechanism.
SN₂ Mechanism is mechanism involving the factors of steric hindrance following the order of 1° > 2° > 3°. It is a Nucleophilic substitution reaction.
Williamson Ether Synthesis is the synthesis of ether through SN₂ mechanism in which an ether is treated with conc. H₂SO₄ at moderate temperature.
When hexan-1-ol is treated with conc. H₂SO₄ at moderate temperatures, Di-n-hexyl ether is formed as below:
CH₃CH₂CH₂CH₂CH₂CH₂OH +Conc. H₂SO₄-->(CH₃CH₂CH₂CH₂CH₂CH₂)₂0
Hexan-1-ol Di-n-hexyl ether
Williamson Ether Synthesis is a reaction involving a alcohol that is deprotonated to form an ether.
Learn more about Williamson Ether Synthesis here, brainly.com/question/2622808
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a. The mass is greater before the change occurs.
Answer:
6.2g of NaBr are produced
Explanation:
The reaction of HBr with NaOH occurs as follows:
HBr + NaOH → NaBr + H2O
<em>Where 1 mole of each reactant produce 1 mole of NaBr</em>
To solve this question we need to find the moles of each reactant using their molar mass. With moles we can find limiting reactant and the moles (And mass) of NaBr produced, as follows:
<em>Moles HBr -Molar mass: 80.9119g/mol)-</em>
4.9g * (1mol/80.9119g) = 0.0606 moles HBr
<em>Moles NaOH -Molar mass: 40g/mol-</em>
3.86g * (1mol/40g) = 0.0965 moles NaOH
As the reaction is 1:1 and the moles of HBr < Moles NaOH, the limiting reactant is HBr and moles of NaBr produced are 0.0606 moles.
The mass of NaBr (Molar mass: 102.894g/mol) is:
0.0606 moles * (102.894g/mol) =
<h3>6.2g of NaBr are produced</h3>
