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sukhopar [10]
3 years ago
7

Determine the distance of closest approach (in fm) before the alpha particle reverses direction. Assume the lead nucleus remains

stationary. Assume the alpha particles are initially very far from a stationary lead nucleus.
Chemistry
1 answer:
kiruha [24]3 years ago
7 0

Answer:

Take E(alpha particle energy) = 5.5 MeV (5.5x106x1.6x10-19)

If the charge on the lead nucleus is +82e(atomic number of lead is 82) = +82x1.6x10-19 C and the charge on the alpha particle is +2e = 2x1.6x10-19 C

Using dc = (1/4πεo)qQ/Eα we have

dc = [9x10^9x(2x1.6x10-19x82x1.6x10-19)]/5.5x10-13 = 6.67x10^-13m. = 6.67 x 10^-13 x 10^15 = 6.67 x 10^2fm

Note: 1meter = 10^15fentometer

Explanation:

This is well inside the atom but some eight nuclear diameters from the centre of the lead nucleus.

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4 0
3 years ago
Read 2 more answers
C5H12 + 8O2 → 5CO2 + 6H2O<br><br> Calculate the energy change for the reaction:
KATRIN_1 [288]
C5H12 (l) + 8O2 (g) ----> 5CO2 (g) + 6H2O (l)
Delta H = -3505.8 kJ/mol

C (s) + O2 (g) -----> CO2 (g)
Delta H = -393.5 kJ/mol

H2 (g) + (1/2)O2 (g) ------> H2O (l)
Delta H = -286 kJ/mol

Possible answers:
a. +35 kJ/mol
b. + 1,073 kJ/mol
c. -4,185 kJ/mol
d. -2,826 kJ/mol
e. -178 kJ/mol
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If 1.00L of water is added to 3.00 L
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What are valence electrons? how many of a magnesium atom’s 12 electrons are valence electrons?
wlad13 [49]

It has 2 valence electrons.

6 0
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Please help with the question above!
Sergio [31]

Answer:

B

Explanation:

B

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