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emmainna [20.7K]
3 years ago
12

How do you do Pythagorean theorem

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0
Pythagorean theorem is a^2 + b^2 = c^2
2. You are trying to find x which is c^2
so plug in the other numbers to the other letters. 9^2 + 17^2 = c^2
9^2= 81. 17^2= 289
81 + 289 = 370
370= c^2
Now all you have to do is square root the number
*square root sign* 370
19.24
c = 19.24
So, x = 19.24
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Secure a future for upcoming generation

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3 years ago
The diagram shows a circle inside a square.<br> a O<br> 16 cm<br> Work out the area of the circle.
LuckyWell [14K]

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perimeter of circle=2πr

16=2πr

r=16/2π=8/πcm

now.

area of circle=πr²=π(8/π)²=π×64/π²=64/(22/7)=64×7/22=20.36cm²

4 0
2 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

3 0
2 years ago
2) Kari is flying her kite at the park. She has let
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Answer:

approx 58 yard we can determine it by pithagoras theorem

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3 years ago
(8x-5) (2x) (3x-10). what is the largest angle??
kompoz [17]
8x-5 would be the largest angle because as you approach a larger and larger x value, 8x-5 will skyrocket past the other two. Also when you plug in a low value like 1, 8x-5=3, which is still higher than the other two. The only exception is if you plug in a negative x value which is impossible.
8x-5
5 0
3 years ago
Read 2 more answers
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