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emmainna [20.7K]
3 years ago
12

How do you do Pythagorean theorem

Mathematics
1 answer:
ser-zykov [4K]3 years ago
6 0
Pythagorean theorem is a^2 + b^2 = c^2
2. You are trying to find x which is c^2
so plug in the other numbers to the other letters. 9^2 + 17^2 = c^2
9^2= 81. 17^2= 289
81 + 289 = 370
370= c^2
Now all you have to do is square root the number
*square root sign* 370
19.24
c = 19.24
So, x = 19.24
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For a square with a side length x + 1 , what is the area if x=9
Svetach [21]

Answer:

100 units squared

Step-by-step explanation:

The area of a square is A=s^2, where s is the side length. So, in your problem, the area would be A=(x+1)^2. If x = 9, then the formula would be A = (9+1)^2 = 100.

6 0
3 years ago
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Find the measure of angle X in the triangle below.
Elan Coil [88]

Answer:

  X = 89.92° or 90.08°

Step-by-step explanation:

The law of sines can be used to find the value of angle X:

  sin(X)/26 = sin(67.38°)/24

  sin(X) = (26/24)sin(67.38°) ≈ 0.99999901787

There are two values of X that have this sine:

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  X = 180° -arcsin(0.99999901787) ≈ 90.08°

There are two solutions: X = 89.92° or 90.08°.

_____

<em>Comment on the problem</em>

We suspect that the angle is supposed to be considered to be 90°. However, the given angle is reported to 2 decimal places, so we figure the requested angle should also be reported to 2 decimal places.

The lengths of the short side that correspond to the above angles are 10.03 and 9.97 units. If the short side were considered to be 10 units, the triangle would be a right triangle, and the larger acute angle would be ...

  arcsin(24/26) ≈ 67.38014° . . . . rounds to 67.38°

This points up the difficulty of trying to use the Law of Sines on a triangle that is actually a right triangle.

3 0
3 years ago
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Juan invested $100 in a savings account the earns 5% annually. The value, A, of the investment can be calculated using the equat
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Answer:

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Step-by-step explanation:

Step one:

given

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Required

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substituting we have

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