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Snezhnost [94]
3 years ago
13

How many moles of oxygen would be required to produce 5 mol of water? (Remember sig figs)

Chemistry
1 answer:
Vikki [24]3 years ago
7 0

Answer:

Since moles are just "some number of particles", and since one O2 molecule contains enough oxygen for two H2O molecules, you need 2.5 moles of O2 for 5 moles of H2O.

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324.55 cm - (6104.5 cm²/22.3 cm)
Ganezh [65]

Answer: 50.806 cm is the correct answer.

Explanation: First divide 6104.5 cm^2 by 22.3 cm.

\frac{6104.5cm^2}{22.3cm} = 273.74 cm

*Note: When dividing units, subtract the exponents, and when multiplying units simply add the exponents.

Then continue by subtracting 324.55 cm - 273.74 cm.

This should give you an answer of 50.806 cm.

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2 years ago
What is a laboratory
Zepler [3.9K]

a place where people can perform experiments

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3 years ago
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Help pleaseeeeeee
Vika [28.1K]

Answer:

20. ²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He

21. ⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca

Explanation:

20. ²⁴¹₉₅Am —> __ + ⁴₂He

Let ⁿₘX be the unknown.

Thus, the equation becomes:

²⁴¹₉₅Am —> ⁿₘX + ⁴₂He

Next, we shall determine n, m and X. This can be obtained as follow:

241 = n + 4

Collect like terms

n = 241 – 4

n = 237

95 = m + 2

Collect like terms

m = 95 – 2

m = 93

Thus,

ⁿₘX => ²³⁷₉₃X => ²³⁷₉₃Np

Therefore, the complete equation is:

²⁴¹₉₅Am —> ²³⁷₉₃Np + ⁴₂He

21. __ —> ⁰₋₁β + ⁴²₂₀Ca

Let ʸₓZ be the unknown.

Thus, the equation becomes:

ʸₓZ —> ⁰₋₁β + ⁴²₂₀Ca

Next, we shall determine y, x and Z. This can be obtained as follow:

y = 0 + 42

y = 42

x = –1 + 20

x = 19

Thus,

ʸₓZ => ⁴²₁₉Z => ⁴²₁₉K

Therefore, the complete equation is:

⁴²₁₉K —> ⁰₋₁β + ⁴²₂₀Ca

3 0
3 years ago
How many molecules of water are there in 0.80 Mol of water?
sdas [7]

4.816 x 10^23, because the number of atoms in one mole of any compound, mixture, or pure substance is 6.02 x 10^23, and multiplying that by 0.8 moles you get that there are 4.816 x 10^23 atoms in 0.8 moles of water.

7 0
3 years ago
CORRECT ANSWER GETS BRAINEST! ✨
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Answer:

The answer is Non-Metals

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