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Snezhnost [94]
3 years ago
13

How many moles of oxygen would be required to produce 5 mol of water? (Remember sig figs)

Chemistry
1 answer:
Vikki [24]3 years ago
7 0

Answer:

Since moles are just "some number of particles", and since one O2 molecule contains enough oxygen for two H2O molecules, you need 2.5 moles of O2 for 5 moles of H2O.

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Match the term with the definition.
Tom [10]
Condensation goes with A.

Evaporation goes with C.

Sublimation goes with B.

Freezing goes with D.
6 0
3 years ago
If the mass of a block of wood is 4.6g and the density is 0.98g/mL what is the volume.
irina [24]

Answer:

The answer is

<h2>4.69 mL</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass of wood = 4.6 g

density = 0.98 g/mL

It's volume is

volume =  \frac{4.6}{0.98}  \\  = 4.69387755...

We have the final answer as

<h3>4.69 mL</h3>

Hope this helps you

3 0
4 years ago
Static electricity is
Luda [366]
Hey there !

The answer is C. build up of electrical charges by friction


Static electricity is a stationary electric charge, typically produced by friction, which causes sparks or crackling or the attraction of dust or hair.

Hope this helps !
6 0
3 years ago
What is the formula for hexaboron tetrabromide
Sveta_85 [38]

Answer:

The formula for the compound isB6Br7

6 0
3 years ago
Determine the specific heat of a material if a 35-9 sample absorbed 96 ) as it was heated from 293 Kto 313 K.
Norma-Jean [14]

This is an incomplete question, here is a complete question.

Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.

Answer : The specific heat of a material is, 0.137 J/g.K

Explanation :

Formula used to calculate the specific heat of a material is:

q=m\times c\times (T_2-T_1)

where,

q = heat absorbed = 96 J

m = mass of sample = 35 g

c = specific heat capacity of material = ?

T_1 = initial temperature = 293 K

T_2 = final temperature = 313 K

Now put all the given values in the above formula, we get:

96J=35g\times c\times (313-293)K

c=0.137J/g.K

Therefore, the specific heat of a material is, 0.137 J/g.K

5 0
4 years ago
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