Answer:
43.868 J
Explanation:
Kinetic energy of a body is the amount of energy possessed by a moving body. The SI unit of kinetic energy is the joule (kg⋅m²⋅s⁻²).
According to classical mechanics, kinetic energy = 1/2 m·v²
Where, m= mass in kg and v= velocity in m/s
Given: m = 19.2 lb and v = 7.10 miles/h
Since, 1 lb= 0.453592 kg
∴ m = 19.2 lb = 19.2 × 0.453592 kg = 8.709 kg
Also, 1 mi = 1609.34 m and 1 h = 3600 sec
∴ v = 7.10 mi/h = 7.10 × 1609.34 m ÷ 3600 sec = 3.174 m/sec
Therefore, <u>kinetic energy of the goose</u> = 1/2 m·v² = 1/2 × (8.709 kg)× (3.174 m/sec)² = 43.868 J
Answer:
There is nothing attached to this question so I unfortunately cannot help you
Explanation:
There are 6.33 × 10²⁵ hydrogen atoms in this solution in total.
<h3>Explanation</h3>
- There are two hydrogen atoms in each water
molecule. - There are three hydrogen atoms in each ammonia
molecule.
2.10 × 10²⁵ water molecules and 7.10 × 10²⁴ ammonia molecules will contain
hydrogen atoms in total.
Answer:
68133080.02 g
Explanation:
I believe that the question is to find the mass of air in the room and not the molar mass of air since the molar mass of air was already given in the question as 28.97 g/mol.
Now, if 1 mole of a gas occupies 22.4 L
x moles of air occupies 52,681,428.8 Liters
x = 1 * 52,681,428.8 /22.4
x = 2351849.5 moles of air
Now, number of moles = mass/ molar mass
but molar mass = 28.97 g/mol
2351849.5 = mass/28.97
mass = 2351849.5 * 28.97
mass = 68133080.02 g
I don’t actually know for sure, but I think it would sink. Most of the mass of the molecule is from the oxygen.
Amu of O2 = 32
Amu of C = 12
And since most of the balloon is oxygen, it has no reason to actually float. It would be denser than the air, I’d imagine. I could be totally wrong here, I’m guessing based on my knowledge of chemistry
