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Thepotemich [5.8K]
3 years ago
9

Why is a solution not a pure substance?

Chemistry
1 answer:
r-ruslan [8.4K]3 years ago
7 0
I think it is b  sorry if wrong
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A 25.0 L tank of nitrogen gas is at 25 oC and 2.05 atm . If the temperature stays at 25 oC and the volume is decreased to 14.5 L
NeTakaya

Answer:

\boxed {\boxed {\sf P_2 \approx 3.53 \ atm}}

Explanation:

In this problem, the temperature stays constant. The volume and pressure change, so we use Boyle's Law. This states that the pressure of a gas is inversely proportional to the volume. The formula is:

P_1V_1=P_2V_2

Now we can substitute any known values into the formula.

Originally, the gas has a volume of 25.0 liters and a pressure of 2.05 atmospheres.

25.0 \ L * 2.05 \ atm = P_2V_2

The volume is decreased to 14.5 liters, but the pressure is unknown.

25.0 \ L * 2.05 \ atm = P_2 * 14.5 \ L

Since we are solving for the new pressure, or P₂, we must isolate the variable. It is being multiplied by 14.5 liters and the inverse of multiplication is division. Divide both sides by 14.5 L .

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}=\frac{P_2 *14.5 \ L}{14.5 \ L}

\frac {25.0 \ L * 2.05 \ atm }{14.5 \ L}= P_2

The units of liters cancel.

\frac {25.0  * 2.05 \ atm }{14.5 }=P_2

\frac {50.25\  atm }{14.5 }=P_2

3.53448276 \ atm = P_2

The original values of volume and pressure have 3 significant figures, so our answer must have the same.

For the number we found, that is the hundredth place.

  • 3.53448276

The 4 in the thousandth place (in bold above) tells us to leave the 3 in the hundredth place.

3.53 \ atm \approx P_2

The new pressure is approximately <u>3.53 atmospheres.</u>

8 0
3 years ago
The density of a metal cube is 8 x103 kg/m3. Convert
Rom4ik [11]

Answer:

Explanation:

[peirod4

4 0
3 years ago
I NEED HELP PLEASE! :)
Dmitrij [34]

Answer:

Explanation:

SF4 forms a trigonal bipyramidal shape and its molecular shape is that of a "see-saw".

Since sulfur is in 3rd period, it violates the octet rule and has more than 8 electrons accompanying its valence shell.

Here's a picture of lewis structure and electron geometry.

5 0
3 years ago
4. Calculate the relative molecular masses of the following substances [RAM: H=1, O=16, S=32, C=12, N=14] a. CH2(NH2)COOH b. H2S
8090 [49]

Answer:

a. CH2(NH2)COOH

molecular \: mass = (12 \times 2) + (5 \times 1) + (14 \times 1) + (16 \times 2)  \\  = 24 + 5 + 14 + 32 \\  = 75 \: grams

b. H2SO4

molecular \: mass = (2 \times 1) + 32 + (16 \times 4) \\  = 2 + 32 + 64\\  = 98 \: grams

4 0
3 years ago
20 points!
Paladinen [302]

Answer:

c and d

Explanation:

mitochondria and vacoule

8 0
3 years ago
Read 2 more answers
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