helium gas in a 2.00 L cylinder is under 1.12 atm pressure. At 36.5°C that same gas sample has a pressure of 2.56 atm. What was
the initial temperature of the gas in the cylinder?
1 answer:
Answer:
T₁ = 135.41 K
Explanation:
Given data:
Initial pressure = 1.12 atm
Finial temperature = 36.5 °C (36.5 +273 = 309.5 K)
Initial temperature = ?
Final pressure = 2.56 atm
Formula:
P₁/T₁ = P₂/T₂
P₁ = Initial pressure
T₁ = Initial temperature
P₂ = Final pressure
T₂ = Final temperature
Solution:
P₁/T₁ = P₂/T₂
T₁ = P₁T₂ /P₂
T₁ = 1.12 atm × 309.5 K / 2.56 atm
T₁ = 346.64 atm . K / 2.56 atm
T₁ = 135.41 K
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