Answer:
I'm confused you did not provide the graph that is referenced on this question...
Notice that
(1 - <em>x</em>)⁵ (1 + 1/<em>x</em>)⁵ = ((1 - <em>x</em>) (1 + 1/<em>x</em>))⁵ = (1 - <em>x</em> + 1/<em>x</em> - 1)⁵ = (1/<em>x</em> - <em>x</em>)⁵
Recall the binomial theorem:
Let <em>a</em> = 1/<em>x</em>, <em>b</em> = -<em>x</em>, and <em>n</em> = 5. Then
We get an <em>x</em> ³ term for
2<em>k</em> - 5 = 3 ==> 2<em>k</em> = 8 ==> <em>k</em> = 4
so that the coefficient would be
Answer:
9x^2 + 15x -6
Step-by-step explanation:
Your problem → If f(x) = x^2 + 7x and g(x) = 3x - 1, find f(g(x))?
f(x)=x2+7x,g(x)=3x-1,fog(x)=?
g(x)=3x-1,f(x)=x2+7x
fog(x)=f(g(x))
=f(3x-1)
=(3x-1)2+7⋅(3x-1)
=(3x-1)2+21x-7
=(9x2-6x+1)+21x-7
=9x2+15x-6
fog(x)=9x2+15x-6
Answer: -The mean is not affected by the existence of an outlier.
Step-by-step explanation:
An outlier is an ultimate value in a set of data that is very much higher or lower than the other numbers. Mean is the only central tendency which is affected by the outlier. (It also affect the standard deviation)
It can affect the mean of a data set by skewing the results so that the mean is no longer representative of the data set.
The median and the interquartile range is unaffected by the existence of an outlier.
