Answer
current density is given by

where J = σ E

now,

a) Electric field strength at the inner surface of an iron cylinder
a = 0.5 cm = 0.005 m b = 2.3 = 0.023
L = 10 cm = 0.1 m I = 27 A


E = 8.59 x 10⁻⁴ V/m
b) Electric field strength at the outer surface of an iron cylinder
a = 0.5 cm = 0.005 m b = 2.3 = 0.023
L = 10 cm = 0.1 m I = 27 A


E =1.87 x 10⁻⁴ V/m
Answer:
B because 17100 is the half of the carbon
Answer:
<em>The density of rock = 3.37 g/cm³</em>
Explanation:
Density: Density can be defined as the ratio of the mass of a body to the volume. The S.I unit of density is kg/m³. It can be expressed mathematically as ,
D = M/V............................................... Equation 1
Where D = density of the body, M = mass of the body, V = volume of the body.
From Archimedes' principle, a body will displace a volume of water equal to its volume.
Therefore, Volume of the object = volume of water displaced
<em>Given: M = 300 g, V = volume of water displace = 89.0 cm³.</em>
<em>Substituting these values into equation 1</em>
<em>D = 300/89</em>
<em>D = 3.37 g/cm³</em>
<em>The density of rock = 3.37 g/cm³</em>
Answer:
1.8m
Explanation:
Let the Elastics of the steel ASTM-36 
The strain of the bar when subjected to 150 MPa is

Therefore, if the bar elongates by 1.35 mm, then the original length L would be:

or 1.8m
Answer:
14869817.395 m
Explanation:
=22 microarcsecond
λ = Wavelength = 1.3 mm
Converting to radians we get

From Rayleigh Criterion

Diameter of the effective primary objective is 14869817.395 m
It is not possible to build one telescope with a diameter of 14869817.395 m. But, we need this type of telescope. So, astronomers use an array of radio telescopes to achieve a virtual diameter in order to observe objects that are the size of supermassive black hole's event horizon.