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3 years ago

7

An inductor with an inductance of .5 henrys (H) is to be connected to a 60 Hz circuit. What will the inductive reactance (X L) b

e

1 answer:

Anika [276]3 years ago

4 0

Answer:

1885.2 ohms

Explanation:

Step one:

given data

L=5H

f=60Hz

Required

The inductive reactance of the inductor

Step two:

Applying the expression

XL= 2πfL

substitute

XL=2*3.142*60*5

XL=1885.2 ohms

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DerKrebs [107]

The ball's horizontal and vertical velocities at time $t$ are

$v_x=v_{xi}$

$v_y=v_{yi}-gt$

but the ball is thrown horizontally, so $v_{yi}=0$ . Its horizontal and vertical positions at time $t$ are

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$y=20.0\,\mathrm m-\dfrac g2t^2$

The ball travels 22 m horizontally from where it was thrown, so

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from which we find the time it takes for the ball to land on the ground is

$t=\dfrac{22\,\rm m}{v_{xi}}$

When it lands, $y=0$ and

$0=20.0\,\mathrm m-\dfrac{9.8\frac{\rm m}{\mathrm s^2}}2\left(\dfrac{22\,\rm m}{v_{xi}}\right)^2$

$\implies v_i=v_{xi}=11\dfrac{\rm m}{\rm s}$

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3 years ago

When I wave a charged golf tube at the front of the classroom with a frequency of two oscillations per second, I produce an elec

solmaris [256]

To solve this problem it is necessary to apply the concepts related to Wavelength depending on the frequency and speed of light.

The equation that meets these parameters is given by

$\lambda = \frac{c}{f}$

Where,

c = Speed of light

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Our values are given as

$c = 3*10^8m/s \rightarrow$ velocity of light in free space

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Replacing we have that

$\lambda = \frac{c}{f}\\\lambda = \frac{3*10^8}{2}\\\lambda = 1.5*10^8m$

Therefore the correct answer is B.

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3 years ago

Suppose that the average speed (vrms) of carbon dioxide molecules (molar mass 44.0 g/mol) in a flame is found to be 2.67 105 m/s

34kurt

Answer:

$T = 1.26 \times 10^8 K$

Explanation:

As we know that rms speed of ideal gas is given by the formula

$v_{rms} = \sqrt{\frac{3RT}{M}}$

here we know that

$v_{rms} = 2.67 \times 10^5 m/s$

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$M = 44 g/mol = 0.044 kg/mol$

now from above formula we have

$2.67\times 10^5 = \sqrt{\frac{3(8.31)T}{0.044}}$

now we have

$T = 1.26 \times 10^8 K$

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4 years ago

Rearrange the equation = KE<br> -1<br> 2<br> - my? to solve for v. Show your work.

vesna_86 [32]

Answer:

See below

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KE = 1/2 m v^2 multiply both sides by 2

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2(KE) / m = v^2 sqrt both sides

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2 years ago

A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the high

m_a_m_a [10]

Answer:

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Explanation:

given data

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ripples decrease to = 4.7 cm

solution

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KE = (0.5) × m × A² × ω² .................1

and kinetic energy is directly proportional to square of the amplitude.

so

$\frac{KE2}{KE1} = \frac{A2^2}{A1^2}$ .............2

$\frac{KE2}{KE1} = \frac{4.7^2}{6.5^2}$

$\frac{KE2}{KE1}$ = 0.52284

so factor that bug maximum KE change is 0.52284

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4 years ago