We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is
X=0m/s
From the question we are told that
mosquito flying 2 m/s
against a 2 m/s headwind
Generally
The speed over the ground is the Flight Speed minus resistance speed
Generally the equation for the speed over the ground is mathematically given as
X=Flight Speed-resistance speed
Therefore
X=2-2
X=0m/s
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Answer:
1995 and 2000 , 4 trillions
Explanation:
100 J
Explanation:
multiply the force by the distance
20 N x 5 meters = 100 J
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85 N - 40 N = 45 N
And depending on direction the greater force is being pulled towards
To stop the car it would be 100m because if the car is going to 65km/h then it would still be 100km/h
