Question

A A load of 1000 N can be lifted by applying

Answer 1

Answer:

Explanation:

$\text{Since the fulcrum lies in between the load and effort, it is class I lever.}$

$\text{Mechanical advantage (M.A.) of levers is given by,}$

$\text{M.A.=effort armload arm=50cm,10cm}$

$\text{Thus, mechanical advantage , M.A. = 5.}$

$\text{Given, effort (E)=10N, Load(L)=?}$

∴ $L=E \times M.A.$

$=10\times5=50N$

Answer 2

Answer:

$\fbox {100 cm}$

Explanation:

Finding Mechanical Advantage :

MA = Load / Effort

MA = 1000/250

MA = 4

Finding length of effort arm :

Load arm = Effort arm / 4

Effort arm = 25 cm x 4

Effort arm = 100 cm