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nika2105 [10]
3 years ago
6

Which polygon appears to be regular?

Mathematics
1 answer:
il63 [147K]3 years ago
4 0

Answer:

The polygon that appears to be regular is Figure B the parallelogram

Step-by-step explanation:

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Using the table below, find the mean and median of the set of data.
Schach [20]

The mean of the data set is 81.6.

The median of the data set is 80.

<h3>What is mean?</h3>

The mean is the average of a data set. Therefore,

Mean = (70 x 2 + 75 x 8 + 80 x 6 + 85 x 3 + 90 x 9) / 28 = 81.6.

Hence,

mean = 81.6

<h3>What is a median?</h3>

Median is a statistical measure that determines the middle value of a dataset listed in ascending order .

Therefore,

28 / 2 = 14

median = 80 + 80 / 2 = 160 / 2 = 80

learn more on mean and median here: brainly.com/question/28052298

#SPJ1

5 0
2 years ago
What is the slope of a trend line that passes through the points (5, 80) and (7, 65)?​
Mila [183]

Answer:

(65-80)/(7-5) = -15/2

Step-by-step explanation:

hmu for an explanation

3 0
4 years ago
Read 2 more answers
Question in picture solve
Luda [366]

Answer:

25

Step-by-step explanation:

165-140=25

140-115=25

115-90=25

90-65=25

65-40=25

4 0
3 years ago
For the function​ below, find a formula for the upper sum obtained by dividing the interval [a comma b ][a,b] into n equal subin
Vlad [161]

Answer:

See below

Step-by-step explanation:

We start by dividing the interval [0,4] into n sub-intervals of length 4/n

[0,\displaystyle\frac{4}{n}],[\displaystyle\frac{4}{n},\displaystyle\frac{2*4}{n}],[\displaystyle\frac{2*4}{n},\displaystyle\frac{3*4}{n}],...,[\displaystyle\frac{(n-1)*4}{n},4]

Since f is increasing in the interval [0,4], the upper sum is obtained by evaluating f at the right end of each sub-interval multiplied by 4/n.

Geometrically, these are the areas of the rectangles whose height is f evaluated at the right end of the interval and base 4/n (see picture)

\displaystyle\frac{4}{n}f(\displaystyle\frac{1*4}{n})+\displaystyle\frac{4}{n}f(\displaystyle\frac{2*4}{n})+...+\displaystyle\frac{4}{n}f(\displaystyle\frac{n*4}{n})=\\\\=\displaystyle\frac{4}{n}((\displaystyle\frac{1*4}{n})^2+3+(\displaystyle\frac{2*4}{n})^2+3+...+(\displaystyle\frac{n*4}{n})^2+3)=\\\\\displaystyle\frac{4}{n}((1^2+2^2+...+n^2)\displaystyle\frac{4^2}{n^2}+3n)=\\\\\displaystyle\frac{4^3}{n^3}(1^2+2^2+...+n^2)+12

but  

1^2+2^2+...+n^2=\displaystyle\frac{n(n+1)(2n+1)}{6}

so the upper sum equals

\displaystyle\frac{4^3}{n^3}(1^2+2^2+...+n^2)+12=\displaystyle\frac{4^3}{n^3}\displaystyle\frac{n(n+1)(2n+1)}{6}+12=\\\\\displaystyle\frac{4^3}{6}(2+\displaystyle\frac{3}{n}+\displaystyle\frac{1}{n^2})+12

When n\rightarrow \infty both \displaystyle\frac{3}{n} and \displaystyle\frac{1}{n^2} tend to zero and the upper sum tends to

\displaystyle\frac{4^3}{3}+12=\displaystyle\frac{100}{3}

8 0
4 years ago
Use a diagram to solve: Sara ran two-fifths of the race. She needs to run 120 m more to finish the race. What is the length of t
KATRIN_1 [288]
The answer would be 200 meters.
7 0
3 years ago
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