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Arada [10]
3 years ago
8

Find the indefinite integral. (use c for the constant of integration.) sin3 5θ cos 5θ dθ

Mathematics
1 answer:
Elina [12.6K]3 years ago
7 0

I'm guessing you mean

\displaystyle\int\sin^35\theta\cos5\theta\,\mathrm d\theta

Let t=5\sin\theta. Then \mathrm dt=5\cos5\theta\,\mathrm d\theta. So we have

\displaystyle\int\sin^35\theta\cos5\theta\,\mathrm d\theta=\frac15\int\sin^35\theta(5\cos5\theta)\,\mathrm d\theta

=\displaystyle\frac15\int t^3\,\mathrm dt

=\dfrac{t^4}{20}+C

=\dfrac{\sin^4\5\theta}{20}+C

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