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Arada [10]
3 years ago
8

Find the indefinite integral. (use c for the constant of integration.) sin3 5θ cos 5θ dθ

Mathematics
1 answer:
Elina [12.6K]3 years ago
7 0

I'm guessing you mean

\displaystyle\int\sin^35\theta\cos5\theta\,\mathrm d\theta

Let t=5\sin\theta. Then \mathrm dt=5\cos5\theta\,\mathrm d\theta. So we have

\displaystyle\int\sin^35\theta\cos5\theta\,\mathrm d\theta=\frac15\int\sin^35\theta(5\cos5\theta)\,\mathrm d\theta

=\displaystyle\frac15\int t^3\,\mathrm dt

=\dfrac{t^4}{20}+C

=\dfrac{\sin^4\5\theta}{20}+C

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Read 2 more answers
you are taking a test worth 130 points. There are a total of 50 five-point and two-point questions. How many five-point question
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10 five-point questions and 40 two-point questions

Step-by-step explanation:

Let x represent the total number of five-point questions and y represent the total number of two-point questions.

Equation 1:     5x+2y=130

Equation 2:     x+y=50

Multiplying Equation 2 by 2:     2x+2y=100     (Equation 3)

(Equation 1) - (Equation 3):     3x=30

                                                  x=10

Substituting x=10 into x+y=50:     10+y=50

                                                            y=40

Therefore, there are 10 five-point questions and 40 two-point questions.


<h2><u>Check</u></h2>

Substituting x=10 and y=40 into Equation 1:

LHS=5x+2y=5(10)+2(40)=50+80=130

RHS=130

LHS=RHS

Substituting x=10 and y=40 into Equation 2:

LHS=x+y=10+40=50

RHS=50

LHS=RHS

Since in both cases the left-hand side is equal to the right-hand side, the answer is correct.

(LHS: left-hand side, RHS: right-hand side)

6 0
3 years ago
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