Answer:
a^2 +b^2=c^2
Given vertices of the triangle are A(4,4),B(3,5) and C(−1,−1)
We know that slope of line passing through the points (x 1,y 1) and (x 2,y 2
) is given by m= x 2−x 1
y
2
−y
1
,x
2
=x
1
Slope of AB i.e.m
1
=
3−4
5−4
=−1
Slope of BC i.e.m
2
=
−1−3
−1−5
=
−4
−6
=
2
3
Slope of CA i.e. m
3
=
4+1
4+1
=
5
5
=1
Clearly, m
1
m
3
=−1
⇒ line segments AB and CA are perpendicular to each other i.e; the given triangle is right angled at A(4,4).
Thus the points (4,4),(3,5) and (1,1) are the vertices of a right angled triangle.
Step-by-step explanation:
Answer:
slope = 4
Step-by-step explanation:
.................
Answer:
=50x+116
Step-by-step explanation:
5+5x(10)−88+200−1
=5+50x+−88+200+−1
Combine Like Terms:
=5+50x+−88+200+−1
=(50x)+(5+−88+200+−1)
=50x+116
Answer:
46
Step-by-step explanation:
Let number is x greater than 21 and x less than 71.
Now, according to question,
21+x=71−x
2x=50
x=25
So, required number is 21+x=21+25=46.
Alternatively,
The required number would be the average or mean of 21 and 71.
So, required number =
2
(21+71)
=46.
The answers are #1 45 #2 24 #3 10