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Basile [38]
3 years ago
10

PLEASE HELP ME I HAVE OTHER HOMEWORK TO BE FINISHED!!

Mathematics
1 answer:
Butoxors [25]3 years ago
4 0

Step-by-step explanation:

Pyramid

1/2 * 12 * 15

6 * 15 = 90

90 * 4 = 360cm

Cube

12 * 12 = 144

144 * 4 = 576cm

576 + 360 =

936 cm² of paint

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Is
Fofino [41]

Answer:

Step-by-step explanation:

A

8 0
3 years ago
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
2 years ago
Find dy/dx | x=-2, given that y=4+4x^2<br><br> Dy/dx| x=-2 =
-Dominant- [34]
Hmmmmmmmmmmmmmmmmmmmmmmmmm
7 0
2 years ago
Read 2 more answers
Witch expressions can be used to calculate the volume of the rectangular prism
svp [43]

Answer:

5

Step-by-step explanation:

the 5

8 0
3 years ago
Plese help me with 5 math questions! 50 points and brainliest! But don't type anything in the answer box until pics are posted!!
lukranit [14]
1. x-5\ \textgreater \ 2

add 5 to both sides

x\ \textgreater \ 3

2. x+2\ \textless \ -5

subtract 2 from both sides

x\ \textless \ -7

3. x-2\ \textless \ 2

add 2 to both sides

x\ \textless \ 4 and it's the 4th graph option

4. x+5 \geq 10

subtract 5 from both sides

x \geq 5 and it's the 2nd graph option

5. x-5\ \textgreater \ -10

add 5 to both sides

x\ \textgreater \ -5

Answers:

1. 3rd option

2. 1st option

3. 4th option

4. 2nd option

5. 2nd option

Hope this helps!


6 0
4 years ago
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