All categories

3 years ago

PLEASE HELP ME I HAVE OTHER HOMEWORK TO BE FINISHED!!

Mathematics

1 answer:

Butoxors [25]3 years ago

4 0

Step-by-step explanation:

Pyramid

1/2 * 12 * 15

6 * 15 = 90

90 * 4 = 360cm

Cube

12 * 12 = 144

144 * 4 = 576cm

576 + 360 =

936 cm² of paint

You might be interested in

Serial numbers for a product are to be made using 2 letters followed by 3 digits. The letters are to be taken from the first 6 l

kvv77 [185]

<h3>Answer: 21600 </h3>

==========================================================

Explanation:

There are 6 letters to pick from {A,B,C,D,E,F} and we have two slots to fill, where no repeats are allowed. This means we have 6*5 = 30 different ways to pick two letters.

There are 10 digits to pick from {0,1,2,...,9} and there are 3 slots to fill. This gives 10*9*8 = 720 different permutations for this portion.

Overall, we have 30*720 = 21600 different serial numbers possible.

3 0

3 years ago

What is the solution to the equation 3 x+ 2 = -x-57<br> X=-8<br> o x=-7<br> o x=7<br> O X=8

luda_lava [24]

Answer:

x = -59/4

Step-by-step explanation:

3 x+ 2 = -x-57

Add x to each side

3 x+x+ 2 = -x+x-57

4x+2 = -57

Subtract 2 from each side

4x +2-2 = -57-2

4x = -59

Divide each side by 4

4x/4 = -59/4

x = -59/4

4 0

3 years ago

Read 2 more answers

Trying to finsh fast so help please

max2010maxim [7]

Answer:

A-B

Step-by-step explanation:

5 0

3 years ago

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

3 years ago

6/13 as a decimal rounded to the nearest thousandth

Tema [17]

Answer:

the answer will be 0.462

Step-by-step explanation:

3 0

2 years ago