Answer:
The correct answer is option (b).
Explanation:
According to the scenario, computation of the given data are as follows:
first we calculate the predetermined OH, then
Predetermined OH rate = Estimated Manufacturing OH Cost ÷ Estimated Direct Labor Hours
= $451,140 ÷ 61,800
= 7.3
So, Applied MOH = 60,500 × 7.3 = $441,650
So, Underapplied OH = Actual MOH - Applied MOH
= $532,000 - $441,650
= $90,350 (under applied)
it's known as fiscal policy
Answer:
$1.3 per share
Explanation:
Data provided in the question:
Number of shares outstanding of TJ = 2,500
Market price = $16.70
Number of shares outstanding of Corner Grocery = 3,000
Price per share of Corner Grocery = $22.50
Cost of acquiring TJ's share = $45,000
Now,
Merger Premium per share = [ Cost of acquiring TJ's share - Market price of TJ's shares ] ÷ Number shares TJ's outstanding
= [ $45,000 - ( $16.70 × 2,500)] ÷ 2,500
= [ $45,000 - $41,750 ] ÷ 2,500
= $3,250 ÷ 2,500
= $1.3 per share
Answer:
this is a cost minimization problem, but it is missing some numbers, so I looked for similar questions (see attached PDF):
minimization equation = 20x₁ + 22x₂ + 18x₃ (costs per ton)
where:
x₁ = mine I
x₂ = mine II
x₃ = mine III
the constraints are:
4x₁ + 6x₂ + x₃ ≥ 54 (high grade ore)
4x₁ + 4x₂ + 6x₃ ≥ 65 (low grade ore)
x₁, x₂, x₃ ≤ 7 (only 7 days per week)
using solver, the optimal solution is
2x₁, 7x₂, and 5x₃
a. The number of days Mine I should operate = <u>2 days
</u>
b. The number of days Mine Il should operate = <u>7 days
</u>
c. The number of days Mine III should operate = <u>5 days
</u>
d. The total cost of the operation for next week = <u>$284,000</u>
