Ask question

Ask question

All categories

2 years ago

7

Y-1/4x=-1 y-2=4x one solution, no solution or infinite solution?

1 answer:

alexandr1967 [171]2 years ago

7 0

Answer:

One solution

Step-by-step explanation:

To start, let's simplify the equations to slope-intercept form

y - 1/4x = =1

+1/4x +1/4x

y = 1/4x - 1

y - 2 = 4x

+2 +2

y = 4x + 2

As you can see, the equations do not have anything in common worth mentioning. The slopes are different and the y-intercepts are different, so there must be only one solution.

Feel free to ask me any questions in the comments! :D

You might be interested in

What are the x-int of the parabola graphed

Vaselesa [24]

Answer:

Step-by-step explanation:

The x-intercepts exist where y is equal to 0...which is ON the x-axis. Hence, the name "x-intercept". These are caled zeros, solutions, and roots. This parabola goes through the x-axis at x = 0 and x = 4. It is at both of these locations where the y-coordinate is 0.

5 0

2 years ago

Read 2 more answers

If the area A of a triangle is 72, and the height h is equal to the length of the base b, what is the length of the base?

alexgriva [62]

Answer:

option B

Step-by-step explanation:

let the height=x

base=x

Area=½bh

72=½x•x

72×2=x²

144=x²

x=√144=12

5 0

2 years ago

Read 2 more answers

Please answer the following, giving Brainliest! Provide me with answers, or answer sheet please :)

IRINA_888 [86]

Answer:

Step-by-step explanation:

you just multiply by 5 to get your answer

7 0

2 years ago

Read 2 more answers

Find the multiplicative inverse of 3 − 2i. Verify that your solution is corect by confirming that the product of

leonid [27]

Answer:

$\frac{3}{13} + \frac{2i}{13}$

Step-by-step explanation:

The multiplicative inverse of a complex number y is the complex number z such that (y)(z) = 1

So for this problem we need to find a number z such that

(3 - 2i) ( z ) = 1

If we take z = $\frac{1}{3-2i}$

We have that

$(3- 2i)\frac{1}{3-2i} = 1$ would be the multiplicative inverse of 3 - 2i

But remember that 2i = √-2 so we can rationalize the denominator of this complex number

$\frac{1}{3-2i } (\frac{3+2i}{3+2i } )=\frac{3+2i}{9-(4i^{2} )} =\frac{3+2i}{9-4(-1)} =\frac{3+2i}{13}$

Thus, the multiplicative inverse would be $\frac{3}{13} + \frac{2i}{13}$

The problem asks us to verify this by multiplying both numbers to see that the answer is 1:

Let's multiplicate this number by 3 - 2i to confirm:

$(3-2i)(\frac{3+2i}{13}) = \frac{9-4i^{2} }{13} =\frac{9-4(-1)}{13}= \frac{9+4}{13} = \frac{13}{13}= 1$

Thus, the number we found is indeed the multiplicative inverse of 3 - 2i

4 0

2 years ago

What is the value of 19.4 Nine is underlined

Readme [11.4K]

Answer:

19

Step-by-step explanation:

iytfgxdzxZXzdxfcgvhbjn,jbhvc

4 0

2 years ago

Read 2 more answers