"f(2)>0" tells you that if you evaluate the function f(x) at 2, the result is: 1) positive, or 2) greater than zero.
Answer:
The system has infinite solutions described in the set 
Step-by-step explanation:
The augmented matrix of the system is
.
We apply row operations:
1. We add the first row to the second row twice and obtain the matrix ![\left[\begin{array}{cccc}-1&-1&-1&4\\0&-1&-2&10\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D-1%26-1%26-1%264%5C%5C0%26-1%26-2%2610%5Cend%7Barray%7D%5Cright%5D)
2. multiply by -1 the rows of the previous matrix and obtain the matrix
that is the reduced echelon form of the matrix associated to the system.
Now we aply backward substitution:
1. Observe that the reduced echelon form has a free variable, then the system has infinite solutions.
2.

3.
.
Then the set of solutions is 
Answer:
p = 26.3
Step-by-step explanation:
Using the law of sines
sin 101 sin 38
--------- = ------------
42 p
Using cross products
p sin 101 = 42 sin 38
p = 42 sin 38 / sin 101
p=26.34175
To the nearest tenth
p = 26.3
Answer:
There is no convincing evidence at α = 0.10 level that the average vertical jump of students at this school differs from 15 inches.
Step-by-step explanation:
We have to make a hypothesis test to prove the claim that the average vertical jump of students differs from 15 inches.
The null and alternative hypothesis are:

The significance level is 0.10.
The sample mean is 17 and the sample standard deviation is 5.37.
The degrees of freedom are df=(20-1)=19.
The t-statistic is:

The two-sided P-value for t=1.67 is P=0.11132.
This P-value is bigger than the significance level, so the effect is not significant. The null hypothesis can not be rejected.
There is no convincing evidence at α = 0.10 level that the average vertical jump of students at this school differs from 15 inches.