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Black_prince [1.1K]
3 years ago
11

If the mass of a sample of Mg is 0.500 g and is placed in 100.0 g of HCl, the heat gained is 546.5 J. What is the change in temp

erature assuming the specific heat of HCl is 4.017 J/K*g?
Chemistry
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

1.36 K

Explanation:

We have the following data:

The heat gained by HCl is calculated as:

heat = m x Sh x ΔT

where m is the mass of HCl (100.0 g), Sh is the specific heat of HCl (4.017 J/K.g) and ΔT is the change in temperature. We introduce the data in the mathematical expression to calculate ΔT as follows:

ΔT = heat/(m x Sh) = 546.5 J/(100.0 g x 4.017 J/K.g) = 1.36 K

Therefore, the change in temperature is 1.36 K.

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A student practicing for a track meet ran 300 meters in 30 seconds. what was her average speed?​
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<h2>10 m/s</h2>

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When solution A was mixed with solution B, the solution turned cloudy, the test tube did not feel warm, and there were no visibl
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Precipitation reaction

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3 0
3 years ago
What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 3.0 ATM and the temperatu
Arisa [49]

Answer:

\boxed {\boxed {\sf P_2= 9 \ atm}}

Explanation:

Since the temperature is held constant, we only need to focus on the volume and pressure. We will use Boyle's Law, which states the volume of a gas is inversely proportional to the pressure. The formula is:

P_1V_1=P_2V_2

Originally, the gas had a volume of 150 milliliters and a pressure of 3.0 atmospheres. We can substitute these values into the left side of the equation.

3.0 \ atm * 150 \ mL = P_2V_2

The original gas was compressed to a volume of 50 milliliters, but we don't know the volume.

3.0 \ atm *150 \ mL= P_2 * 50 \ mL

Now, we need to solve for the new pressure (P₂). Multiply on the left side first.

450 \ atm*mL= P_2 * 50 \ mL

Since we are solving for the pressure, we need to isolate the variable. It is being multiplied by 50 mL. The inverse of multiplication is division. Divide both sides by 50 mL.

\frac{450 \ atm*mL}{50 \ mL}= \frac{P_2 * 50 \ mL}{50 \ mL}

\frac{450 \ atm*mL}{50 \ mL}= P_2

The units of milliliters will cancel.

\frac{450 \ atm}{50 }= P_2

9 \ atm =P_2

The new pressure is <u>9 atmospheres.</u>

8 0
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