Question

How hot will a 2.3 liter balloon have to get to expand to a volume of 7 L? Assume that the initial temperature of the balloon is 25 C?

Answer 1

Answer : The final temperature of balloon will be, 907 K

Explanation :

Charles' Law : It states that volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

We are given:

$V_1=2.3L\\T_1=25^oC=(25+273)K=298K\\V_2=7L\\T_2=?$

Putting values in above equation, we get:

$\frac{2.3L}{298K}=\frac{7L}{T_2}\\\\T_2=906.95K\approx 907K$

Therefore, the final temperature of balloon will be, 907 K