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Stels [109]
3 years ago
11

The Area of a square at right is 72 square units Find the value of X, Did I do this right?

Mathematics
1 answer:
Assoli18 [71]3 years ago
5 0
Yes, your work is correct.

The diagram does illustrate x²+6x+9=72.  This is also represented by

(x+3)² = 72

We can take the square root of both sides:
\sqrt{(x+3)^2}=\sqrt{72}
\\
\\x+3=\pm 6 \sqrt2
\\
\\x+3-3=\pm 6 \sqrt{2} -3
\\
\\x=-3\pm 6\sqrt{2}

When we evaluate this, the answers are x = -11.5 or x = 5.5.
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Dwight creates a table of values for a function and plots the points. He finds that one y value divided by the next y value prod
Mashcka [7]

we know that

The exponential function is of the form

f(x)=a^{x}

where

a is any value greater than 0

In General:

It is always greater than 0, and never crosses the x-axis

It always intersects the y-axis at y=1

Its Domain is the Real Numbers

Its Range is the Positive Real Numbers

Examples

Let

a=3

1) For x=2

f(2)=3^{2} \\ f(2)=9

2) For x=3

f(3)=3^{3} \\ f(3)=27

3) For x=4

f(4)=3^{4} \\ f(4)=81

4) For x=5

f(5)=3^{5} \\ f(5)=243

f(3)/f(2)=\frac{27}{9} \\ =3

f(4)/f(3)=\frac{81}{27} \\ =3

f(5)/f(4)=\frac{243}{81} \\ =3

therefore

the answer is the option

D.) exponential

5 0
3 years ago
Read 2 more answers
Lella will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $46 and costs an ad
Helen [10]
The plans cost the same at 125 miles. the cost is $63.50
6 0
3 years ago
Find the surface area of a square prism with a side measure of 15
Phoenix [80]
Since the length is 15, and the width would be 15, you need to first do 15 x 15.

15 x 15 = 225


Multiply the 6 faces.

225x6

Your final answer would be 1,350.
7 0
3 years ago
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be
babymother [125]

Answer:

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

Step-by-step explanation:

Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.

In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.

8 0
3 years ago
Two circles of radius 8 are tangent to the graph of
KengaRu [80]
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3 years ago
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