Answer:
I'm not sure but i think that it's
x= -7
Hope this helps
1) Answer: The part of the quadratic formula tells us whether the quadratic equation can be solved by factoring is b^2-4ac
2) 4x^2+6x+2=0
ax^2+bx+c=0; a=4, b=6, c=2
b^2-4ac=(6)^2-4(4)(2)=36-32
b^2-4ac=4
Answer: b^2-4ac=4
Answer:The set fee would be $15
Explanation:The set fee is the starting value. This means that it is the value of the y at x = 0 (y-intercept).
To get the set fee, we would first need to get the equation of the line.
Equation of the linear line has the following general formula:
y = mx + c
where m is the slope and c is the y-intercept
1- getting the slope:we are given two points which are:
(20,25) and (50,40)
the slope =

The equation now is:
y = 0.5x + c
2- getting the value of the y-intercept:To get the value of the c, we will use any of the given points, substitute in the equation and solve for c.
I will choose the point (20,25)
y = 0.5x + c
25 = 0.5(20) + c
25 = 10 + c
c = 15
The equation of the line representing the scenario is:y = 0.5x + 15
Now, we know that the value of the c is the y-intercept which is the initial value of the function at x=0.
In our situation, this represents the set fee.
Hope this helps :)
Answer:
Step-by-step explanation:
B. =16x+288x
C. = 1 18 x2+33.52
D.
1752
x
−
162
29
=
−162
29
x+1752
x
=
6(−27x+8468)
29x
=
−162x+50808
29x
F.=
1
12
x+36