Answer:
<u>The Eastbound train speed is 76.5 miles per hour and the Westbound train speed is 79.5 miles per hour.</u>
Step-by-step explanation:
1. Let's review all the information provided for solving this question:
Eastbound train speed = x
Westbound train speed = x + 3 miles per hour (The speed of the westbound train is 3mph greater than the speed of the eastbound train)
Duration of trip = 3 hours
Distance between trains after 3 hours = 468 miles
2. Let's find the speed of each train, using the following equation:
3x + 3(x + 3) = 468
3x + 3x + 9 = 468
6x + 9 = 468
6x = 468 - 9 (Subtracting 9 at both sides)
6x = 459
x = 459/6 (Dividing by 6 at both sides)
x = 76.5 miles per hour
<u>The Eastbound train speed is 76.5 miles per hour and the Westbound train speed is 79.5 miles per hour.</u>
3. Proof that x = 76.5 is correct
3x + 3(x + 3) = 468
3 (76.5) + 3 (76.5 + 3) = 468
229.5 + 238.5 = 468
<u>468 = 468</u>
<u>The value of x = 76. 5 is correct. And now we know that the Eastbound train has traveled 229.5 miles since the departure from Cleveland and the Westbound train 238.5 miles.</u>
Answer:
-3
Step-by-step explanation:
La intercepcion con y se produce cuando x= 0, por lo que si reemplazamos x por 0, queda que y= -3
Answer:
x=4
Step-by-step explanation:
The two angles together are complementary, which means they add up to 90 degrees
solving for x:
9x+4x+38=90
9x+4x=13x
13x+38=90
13x+38-38=90-38
13x=90-38
13x=52
x=4
hope this helps ^D^
Step-by-step explanation:
3x=28+y
x=28+y÷3
then puttingx=28+y÷3
3x=14+y
3(28+y÷3)+y=14
84+3y+3y=42
3y+3y=42-84
y=-42÷6
y=7
so putting y=-7
3x-y=28
3x-7=38
x=38+7÷3
x=15