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ziro4ka [17]
3 years ago
7

Cutting and forming operations performed on relatively thin sheets of metal. a)- True b)-False

Engineering
1 answer:
belka [17]3 years ago
6 0

Answer: True

Explanation: There are different actions that are performed on the metal sheet . Cutting operation is the operation of splitting,slitting or parting of the metal sheet on the by using different kind of blades . Formation operation are basically for the exerting pressure on the sheet to give it desired shape such as bending, squeezing etc. Therefore the given statement is true.

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An organization is struggling to differentiate threats from normal traffic and access to systems. A security engineer has been a
AnnZ [28]

Answer:

Web application Firewall (WAF)

Explanation:

The Web application Firewall (WAF) will be recommended. This will enormously help any organisation that is having a struggle of differentiating threats from normal traffic and access to systems.

WAF is also going to It aggregate data and provide metrics that will assist in identifying malicious actors. Another vital function of WAF will be to block unwanted web traffic from accessing your site. It will protect against hacks, brute force attacks, DDoS attacks, cross-site scripting, SQL injection, and zero-day exploits.

8 0
4 years ago
A train starts from rest at station A and accelerates at 0.4 m/s^2 for 60 s. Afterwards it travels with a constant velocity for
mash [69]
<h3><u>The distance between the two stations is</u><u> </u><u>3</u><u>7</u><u>.</u><u>0</u><u>8</u><u> km</u></h3>

\\

Explanation:

<h2>Given:</h2>

a_1 \:=\:0.4\:m/s²

t_1 \:=\:60\:s

v_{i1} \:=\:0\:m/s

a_2 \:=\:0\:m/s²

t_2 \:=\:25\:min\:=\:1500\:s

a_3 \:=\:-0.8\:m/s²

v_{f3} \:=\:0\:m/s

\\

<h2>Required:</h2>

Distance from Station A to Station B

\\

<h2>Equation:</h2>

a\:=\:\frac{v_f\:-\:v_i}{t}

v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}

v\:=\:\frac{d}{t}

\\

<h2>Solution:</h2><h3>Distance when a = 0.4 m/s²</h3>

Solve for v_{f1}

a\:=\:\frac{v_f\:-\:v_i}{t}

0.4\:m/s²\:=\:\frac{v_f\:-\:0\:m/s}{60\:s}

24\:m/s\:=\:v_f\:-\:0\:m/s

v_f\:=\:24\:m/s

\\

Solve for v_{ave1}

v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}

v_{ave}\:=\:\frac{0\:m/s\:+\:24\:m/s}{2}

v_{ave}\:=\:12\:m/s

\\

Solve for d_1

v\:=\:\frac{d}{t}

12\:m/s\:=\:\frac{d}{60\:s}

720\:m\:=\:d

d_1\:=\:720\:m

\\

<h3>Distance when a = 0 m/s²</h3>

v_{f1}\:=\:v_{i2}

v_{i2}\:=\:24\:m/s

\\

Solve for v_{f2}

a\:=\:\frac{v_f\:-\:v_i}{t}

0\:m/s²\:=\:\frac{v_f\:-\:24\:m/s}{1500\:s}

0\:=\:v_f\:-\:24\:m/s

v_f\:=\:24\:m/s

\\

Solve for v_{ave2}

v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}

v_{ave}\:=\:\frac{24\:m/s\:+\:24\:m/s}{2}

v_{ave}\:=\:24\:m/s

\\

Solve for d_2

v\:=\:\frac{d}{t}

24\:m/s\:=\:\frac{d}{1500\:s}

36,000\:m\:=\:d

d_2\:=\:36,000\:m

\\

<h3>Distance when a = -0.8 m/s²</h3>

v_{f2}\:=\:v_{i3}

v_{i3}\:=\:24\:m/s

\\

Solve for v_{f3}

a\:=\:\frac{v_f\:-\:v_i}{t}

-0.8\:m/s²\:=\:\frac{0\:-\:24\:m/s}{t}

(t)(-0.8\:m/s²)\:=\:-24\:m/s

t\:=\:\frac{-24\:m/s}{-0.8\:m/s²}

t\:=\:30\:s

\\

Solve for v_{ave3}

v_{ave}\:=\:\frac{v_i\:+\:v_f}{2}

v_{ave}\:=\:\frac{24\:m/s\:+\:0\:m/s}{2}

v_{ave}\:=\:12\:m/s

\\

Solve for d_3

v\:=\:\frac{d}{t}

12\:m/s\:=\:\frac{d}{30\:s}

360\:m\:=\:d

d_3\:=\:360\:m

\\

<h3>Total Distance from Station A to Station B</h3>

d\:= \:d_1\:+\:d_2\:+\:d_3

d\:= \:720\:m\:+\:36,000\:m\:+\:360\:m

d\:= \:37,080\:m

d\:= \:37.08\:km

\\

<h2>Final Answer:</h2><h3><u>The distance between the two stations is </u><u>3</u><u>7</u><u>.</u><u>0</u><u>8</u><u> km</u></h3>
7 0
3 years ago
A boiler is used to heat steam at a brewery to be used in various applications such as heating water to brew the beer and saniti
Natalija [7]

Answer:

net boiler heat = 301.94 kW

Explanation:

given data

saturated steam = 6.0 bars

temperature = 18°C

flow rate = 115 m³/h = 0.03194 m³/s

heat use by boiler = 90 %

to find out

rate of heat does the boiler output

solution

we can say saturated steam is produce at 6 bar from liquid water 18°C

we know at 6 bar from steam table

hg = 2756 kJ/kg

and

enthalpy of water at 18°C

hf = 75.64 kJ/kg

so heat required for 1 kg is

=hg - hf

= 2680.36 kJ/kg

and

from steam table specific volume of saturated steam at 6 bar is 0.315 m³/kg

so here mass flow rate is

mass flow rate = \frac{0.03194}{0.315}

mass flow rate m = 0.10139 kg/s

so heat required is

H = h × m  

here h is heat required and m is mass flow rate

H = 2680.36  × 0.10139

H =  271.75 kJ/s = 271.75 kW

now 90 % of boiler heat is used for generate saturated stream

so net boiler heat = \frac{H}{0.90}

net boiler heat = \frac{271.75}{0.90}

net boiler heat = 301.94 kW

5 0
3 years ago
A square steel bar has a length of 8.4 ft and a 2.1 in by 2.1 in cross section and is subjected to axial tension. The final leng
nikitadnepr [17]

Answer:

Poissons ratio = -0.3367

Explanation:

Poissons ratio = Lateral Strain / Longitudinal Strain

In this case, the longitudinal strain will be:

Strain (longitudinal) = Change in length / total length

Strain (longitudinal) = (8.40392 - 8.4) / 8.4

Strain (longitudinal) = 4.666 * 10^(-4)

While the lateral strain will be:

Strain (Lateral) = Change in length / total length

Strain (Lateral) = (2.09967 - 2.1) / 2.1

Strain (Lateral) = -1.571 * 10^(-4)

Solving the poisson equation at the top we get:

Poissons ratio = -1.571 / 4.666                                     <u>( 10^(-4) cancels out )</u>

Poissons ratio = -0.3367

6 0
4 years ago
What are the specifications state that all work shall be done?
Elodia [21]

Answer:

The description including its scope is presented throughout the section below.

Explanation:

  • Such operation must be carried out in compliance with all statutes, legislation, building standards, guidelines, and rules relating to that same task, not all of which are restricted to either the U.S Disability Act, the Ecological laws as well as the workplace Safety Act as modified.
  • This same consultant shall appoint and could be completely liable for almost all processes and sequences just for conducting the Job.
4 0
3 years ago
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