Answer:
Explanation:
Given:
Diameter of aluminum wire, D = 3mm
Temperature of aluminum wire, 
Temperature of air, 
Velocity of air flow 
The film temperature is determined as:

from the table, properties of air at 1 atm pressure
At 
Thermal conductivity,
; kinematic viscosity
; Prandtl number 
The reynolds number for the flow is determined as:

sice the obtained reynolds number is less than
, the flow is said to be laminar.
The nusselt number is determined from the relation given by:
![Nu_{cyl}= 0.3 + \frac{0.62Re^{0.5}Pr^{\frac{1}{3}}}{[1+(\frac{0.4}{Pr})^{\frac{2}{3}}]^{\frac{1}{4}}}[1+(\frac{Re}{282000})^{\frac{5}{8}}]^{\frac{4}{5}}](https://tex.z-dn.net/?f=Nu_%7Bcyl%7D%3D%200.3%20%2B%20%5Cfrac%7B0.62Re%5E%7B0.5%7DPr%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%7B%5B1%2B%28%5Cfrac%7B0.4%7D%7BPr%7D%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5D%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5B1%2B%28%5Cfrac%7BRe%7D%7B282000%7D%29%5E%7B%5Cfrac%7B5%7D%7B8%7D%7D%5D%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D)
![Nu_{cyl}= 0.3 + \frac{0.62(576.92)^{0.5}(0.70275)^{\frac{1}{3}}}{[1+(\frac{0.4}{(0.70275)})^{\frac{2}{3}}]^{\frac{1}{4}}}[1+(\frac{576.92}{282000})^{\frac{5}{8}}]^{\frac{4}{5}}\\\\=12.11](https://tex.z-dn.net/?f=Nu_%7Bcyl%7D%3D%200.3%20%2B%20%5Cfrac%7B0.62%28576.92%29%5E%7B0.5%7D%280.70275%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%7B%5B1%2B%28%5Cfrac%7B0.4%7D%7B%280.70275%29%7D%29%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5D%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5B1%2B%28%5Cfrac%7B576.92%7D%7B282000%7D%29%5E%7B%5Cfrac%7B5%7D%7B8%7D%7D%5D%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%5C%5C%5C%5C%3D12.11)
The covective heat transfer coefficient is given by:

Rewrite and solve for 

The rate of heat transfer from the wire to the air per meter length is determined from the equation is given by:

The rate of heat transfer from the wire to the air per meter length is 
Answer:
1 ) Accuracy of the Machine Tool
2) Load bearing capacity
3) Linearity in the product line
4) Torque of the machine
Explanation:
we know that machine tool is the permanent essential in manufacturing industries
it is a machine use for different form like cutting , grinding and boring etc
so 1st is
1 ) Accuracy of the Machine Tool
we know it is very important Characteristic of the machine tool because when we use it in manufacturing unit Accuracy of the Machine Tool should be higher concern
2) Load bearing capacity
we should very careful about Load bearing capacity because how much amount of load tool will bear check by some parameter like creep , shear stress and strength etc
3) Linearity in the product line
Linearity in the product line mean that it should be group of related product produced by the any one of the manufacturer otherwise it will take time or it may be intermixing
4) Torque of the machine
we know that Torque is a rotational force or a turning force so amount of force multiplied by the distance of the operation
and we know torque per second give the power rating of machine tool
Answer:
Absolute pressure= 57 KPa
Explanation:
Given that
Vacuum gauge pressure = 35 KPa
Atmospheric pressure = 92 KPa
We know that
Absolute pressure=Atmospheric pressure + gauge pressure
But we should remember that Vacuum gauge pressure is also called negative gauge pressure.So when given that pressure is vacuum gauge then subtract gauge pressure from atmospheric pressure instead of addition.
So now by putting the values
Absolute pressure=Atmospheric pressure - Vacuum gauge pressure
Absolute pressure=92 - 35 KPa
Absolute pressure= 57 KPa
Answer:
The correct answers are:
a. % w = 33.3%
b. mass of water = 45g
Explanation:
First, let us define the parameters in the question:
void ratio e =
= 
Specific gravity
=

% Saturation S =
×
=
× 
water content w =
=
a) To calculate the lower and upper limits of water content:
when S = 100%, it means that the soil is fully saturated and this will give the upper limit of water content.
when S < 100%, the soil is partially saturated, and this will give the lower limit of water content.
Note; S = 0% means that the soil is perfectly dry. Hence, when s = 1 will give the lowest limit of water content.
To get the relationship between water content and saturation, we will manipulate the equations above;
w = 
Recall; mass = Density × volume
w = 
From eqn. (2)
= 
∴ 
putting eqn. (6) into (5)
w = 
Again, from eqn (1)

substituting into eqn. (7)

∴ 
With eqn. (7), we can calculate
upper limit of water content
when S = 100% = 1
Given, 
∴
∴ %w = 33.3%
Lower limit of water content
when S = 1% = 0.01

∴ % w = 0.33%
b) Calculating mass of water in 100 cm³ sample of soil (
)
Given,
, S = 50% = 0.5
%S =
×
=
× 
0.50 = 
mass of water = 