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katovenus [111]
3 years ago
13

Find the percent change in cutting speed required to give an 80% reduction in tool life when the value of n is 0.12.

Engineering
1 answer:
vaieri [72.5K]3 years ago
6 0

Answer:21.3%

Explanation:

Given

80 % reduction in tool life

According to Taylor's tool life

VT^n=c

where V is cutting velocity

T=tool life of tool

80 % tool life reduction i.e. New tool Life is 0.2T

Thus

VT^{0.12}=V'\left ( 0.2T\right )^{0.12}

V'=\frac{V}{0.2^{0.12}}

V'=\frac{V}{0.824}=1.213V

Thus a change of 21.3 %(increment) is required to reduce tool life by 80%

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Answer:

using System;

using System.Collections.Generic;

using System.Linq;

public class Problem1 {

public static IEnumerable < int > myFilter(IEnumerable < int > input) {

return input.Where((val, index) => {

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return !(val % 6 == 0 && val < 42);

}).Select((val, index) => {

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}

}

}

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