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3 years ago

10 points!! What is one thing you think a really good engineer should know/develop?...

2 answers:

6 0

Answer:

I think a really good engineer should develop the sense of knowledge of Ohm’s Law.

Basically being able to work out in your head the values of voltage, resistance, current, and power for simple circuits.

-HOLE THAT HELPED!!<3

Katarina [22]3 years ago

3 0

They should know how to successfully take something apart and put it back together again.

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Is an ideal way for a high school student to see what an engineer does on a typical day but does not provide a hands-on experien

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Answer:

Look at some engineering colleges and set up or join a public zoom meeting. For example, some colleges have sign ups for zoom calls on set dates and you‘re able to ask questions.

Explanation:

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3 years ago

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Of the children who die in car crashes, how many of them die due to an improper restraint system (or even just not being buckled

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you died

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3 years ago

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3 years ago

A biotechnology company produced 225 doses of somatropin, including 11 which were defective. Quality control test 15 samples at

Radda [10]

Answer:

0.59

Explanation:

The batch is rejected if any of the random samples are found defective, or, what is the same, it will be accepted only if all 15 samples are good.

The probability that none be defective is the same probability that all the samples are good. Thus, start to calculate the probability that the batch is accepted.

The probability that the first sample is good is 214 /225, because there are 225 - 11 = 214 good samples in 225 doses.

The probability that the second samples is good too is 213/224, because there is 1 less good sample, in the 224 remaining samples.

By the same process, you conclude that the consecutive probabilities of selecting a good sample are: 212/223, 211/222, 210/221, . . . up to 199/211.

The joint probability of all the samples are good is the product of each probability:

$\frac{214}{225}\cdot\frac{213}{224}\cdot\frac{212}{223}\cdot\frac{211}{222}\cdot\frac{210}{221}\cdot\frac{209}{220}\cdot\frac{208}{219}\cdot\frac{207}{218}\cdot\frac{206}{217}\cdot\frac{205}{216}\cdot\frac{204}{215}\cdot\frac{203}{214}\cdot\frac{202}{213}\cdot\frac{201}{212}\cdot\frac{200}{211}\cdot\frac{199}{210}$

The result is: 0.41278 ≈ 0.41

The conclusion is that the probability that all the samples are good and the batch is accepted is 0.41.

Therefore, the probability that the batch is rejected is 1 - 0.41 = 0.59.

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4 years ago