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notka56 [123]
2 years ago
10

100 POINTS EZ |

Mathematics
2 answers:
ehidna [41]2 years ago
7 0
  • Area of the quadrilateral=1/2×diagonal×(sum of perpendiculars)

Put the values

Area:-

\\ \rm\Rrightarrow \dfrac{1}{2}(24)(8+13)

\\ \rm\Rrightarrow 12(21)

\\ \rm\Rrightarrow 252m^2

Anvisha [2.4K]2 years ago
5 0

Answer:

Step-by-step explanation:

Divide the quadrilateral field into two triangles by its diagonal.

Area of a triangle is given by the equation 1/2*base*height.

The top triangle's area = 1/2*24*13 = 156 m^2

The bottom triangle's area = 1/2*24*8 = 96 m^2

Combining, the area of the field = 156 + 96 = 252 m^2

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If y=27 when x= 8 find y when x =11
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Answer:

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Step-by-step explanation:

The problem probably assumes direct variation

y=kx

IF so, then plug in the values and solve for k

27=k(8)

k = 27/8

y= (27/8)x.  Now let x = 11

y = (27/8)11 = 27(11)/8 = 37.125 = 37 1/8

y = 37 1/8

the problem is making some assumption about the relation between x and y.  The simplest assumption that's likely is direct variation,  that x and y are linearly related.  The graph is a straight line through the origin with slope = 27/8

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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