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notka56 [123]
2 years ago
10

100 POINTS EZ |

Mathematics
2 answers:
ehidna [41]2 years ago
7 0
  • Area of the quadrilateral=1/2×diagonal×(sum of perpendiculars)

Put the values

Area:-

\\ \rm\Rrightarrow \dfrac{1}{2}(24)(8+13)

\\ \rm\Rrightarrow 12(21)

\\ \rm\Rrightarrow 252m^2

Anvisha [2.4K]2 years ago
5 0

Answer:

Step-by-step explanation:

Divide the quadrilateral field into two triangles by its diagonal.

Area of a triangle is given by the equation 1/2*base*height.

The top triangle's area = 1/2*24*13 = 156 m^2

The bottom triangle's area = 1/2*24*8 = 96 m^2

Combining, the area of the field = 156 + 96 = 252 m^2

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\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\   \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512

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