Ask question

Ask question

All categories

3 years ago

10

PLEASE HELP WITH THIS QUESTION

1 answer:

Maru [420]3 years ago

8 0

First we can recognize that angle OPQ shares a straight angle with angle QPR, meaning mQPR = 180 - 135 = 45 degrees. Given that angle PRQ is a right angle (90 degrees) and knowing that the interior angles of a triangle dum to 180, we can find that angle PQR (angle Q) is 180 - 90 - 45 = 45 degrees, and

tan(45) = 1

You might be interested in

Plz ANWSER no one else will amwser this

RoseWind [281]

Answer:

1. 80.5

2. 432

3. 310.5

4. 26

Step-by-step explanation:

6 0

4 years ago

Amanda bought 19 packs of cookies for $22.99 from the supermarket. How many packs of cookies can she buy for $59.29?

lbvjy [14]

Answer:

49

Step-by-step explanation:

1.21 x 49 = 59.29

5 0

3 years ago

Please help ASAP thank youu!!

Gennadij [26K]

Answer:

1. (-5)

Step-by-step explanation:

Here you go, glad to help :)

4 0

3 years ago

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

3 years ago

A number increased by 10 is 114 answer in an equation

enyata [817]

We have to make an equation: a number increased by 10 is 114.
An equation is:
x + 10 = 114
x = 114 - 10
x = 104.

7 0

3 years ago

Read 2 more answers