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4 years ago

15

Shawna has a round trampoline in her yard the website where she bought the trampoline said it has a circumference of 12.56 feet

what is the trampoline’s diameter use 3.14 for pie

1 answer:

Greeley [361]4 years ago

4 0

Answer:

4

Formula for diameter:

C/Pi

12.56/3.14

4

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A blimp provides aerial television views of a tennis game. The television camera sights the stadium at a 17degrees angle of depr

BaLLatris [955]

Answer:

1379.31meters is the line-of-sight distance from the television camera to the base of the stadium .

Step-by-step explanation:

As given

A blimp provides aerial television views of a tennis game.

The television camera sights the stadium at a 17degrees angle of depression. The altitude of the blimp is 400m.

Now by using the trignometric identity .

$sin\theta = \frac{Perpendicular}{Hypotenuse}$

As the figure is given below .

Perpendicular = AC = 400 m

Hypotenuse = AB

$\theta = 17^{\circ}$

Putting all the values in the identity .

$sin17^{\circ} = \frac{400}{AB}$

$0.29\ (Approx)= \frac{400}{AB}$

$AB= \frac{400}{0.29}$

AB = 1379.31 meters

Therefore the 1379.31 meters is the line-of-sight distance from the television camera to the base of the stadium .

3 0

3 years ago

a car rental company charges $30 per day to rent a car plus $0.02 per mile driven. which equation represents c, the total cost t

Virty [35]

Answer:

c=0.02(m)+30(5)

or

c= 150+0.02(m)

or

c=0.02(m)+150

or

c=30(5)+0.02(m)

Step-by-step explanation:

This is because c, or cost is equal to 30 dollars a day as a base fee or 150 total for five days plus 0.02 per mile. So, if you multiple the mileage driven by 0.02 and add 150 for the 30$ per day at 5 days. This is your equation

These are just different ways you could write that since it is clear you have a multiple choice question

7 0

3 years ago

What is the slope of the line passing thru the points (-6,-5) (4,4)

Katena32 [7]

Answer:

slope = $\frac{9}{10}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 5) and (x₂, y₂ ) = (4, 4)

m= $\frac{4+5}{4+6}$ = $\frac{9}{10}$

8 0

3 years ago

The length of a rectangle is 3 inches more than it’s width. If the perimeter is 42 inches , find the demensions of the rectangle

slega [8]

Answer:

Step-by-step explanation:

could you provide a picture and i can give you a step by step explanation

3 0

4 years ago

Read 2 more answers

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately <u>298.87</u>.

(b) The number of years before the capital stock exceeds $100,000 is approximately <u>46.15 years</u>.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ <u>46.15 years</u>.

Learn more investment function here:

brainly.com/question/25300925

6 0

3 years ago