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Annette [7]
3 years ago
5

What is the slope of the line passing thru the points (-6,-5) (4,4)

Mathematics
1 answer:
Katena32 [7]3 years ago
8 0

Answer:

slope = \frac{9}{10}

Step-by-step explanation:

Calculate the slope m using the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 5) and (x₂, y₂ ) = (4, 4)

m= \frac{4+5}{4+6} = \frac{9}{10}

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If it takes 16 men 15 days to complete a work,how long will it take 20 men?​
ASHA 777 [7]

Answer:

10 days and 16 hours.

Step-by-step explanation:

15 men work in 16 days to complete the work. So 1 man contributes 16/15 days.  

For 20 men there is an addition of 5 men. [20–15)* 16/15] days = 16/3 days. Substract 16/3 days from 16 days = 16 - (16/3) = 10 days and 16 hours.

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3 years ago
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Step-by-step explanation:

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2 years ago
You wish to compute the 99% confidence interval for the population proportion. How large a sample should you draw to ensure that
Nataly_w [17]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.13}{2.58})^2}=98.47  

And rounded up we have that n=99

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.13 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume the value for \hat p =0.5 since we don't have previous info. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.13}{2.58})^2}=98.47  

And rounded up we have that n=99

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