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3 years ago

What is the next term of the geometric sequence-0.3,0.6,-1.2,2.4

Mathematics

1 answer:

nydimaria [60]3 years ago

6 0

Answer:

4.8 is the next term. Because look at the first one is 0.3. To get the next term we double the numbers all the time. So 0.3 doubles is 0.6, 0.6 is 1.2 and 1.2 is 2.4 and 2.4 is 4.8. It’s your last term. Also you made mistake you put - sign near 1.2. Hope this helps.

Step-by-step explanation:

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Each cube in this rectangular prism is 1 cm3.What is the volume of the rectangular prism?

Lelechka [254]

Answer:

Volume of rectangular prism = $20\ cm^3$

Step-by-step explanation:

Given rectangular prism is made up of small cubes of volume 1 cubic centimeter.

To find volume of rectangular prism.

Solution:

Volume of rectangular prism is = $length\times width \times height$

We know that all sides of a cube are equal in measure.

So, we will count the number of cubes on each side to get the exact measure.

Length side = 4 cubes = 5 cm

Width side = 2 cubes = 2 cm

Height side = 2 cubes = 2 cm

Thus volume of rectangular prism = $5\ cm\times 2\ cm \times 2\ cm$

Volume of rectangular prism = $20\ cm^3$

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3 years ago

. Solve the following equations for x: 3x=30

pishuonlain [190]

$\mathcal \pink{Answer}$

$\mathcal \green{3x = 30}$

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3 0

3 years ago

Read 2 more answers

The angle of elevation from me to the top of a hill is 51 degrees. The angle of elevation from me to the top of a tree is 57 deg

julia-pushkina [17]

Answer:

Approximately $101\; \rm ft$ (assuming that the height of the base of the hill is the same as that of the observer.)

Step-by-step explanation:

Refer to the diagram attached.

Let $\rm O$ denote the observer.
Let $\rm A$ denote the top of the tree.
Let $\rm R$ denote the base of the tree.
Let $\rm B$ denote the point where line $\rm AR$ (a vertical line) and the horizontal line going through $\rm O$ meets. $\angle \rm B\hat{A}R = 90^\circ$ .

Angles:

Angle of elevation of the base of the tree as it appears to the observer: $\angle \rm B\hat{O}R = 51^\circ$ .
Angle of elevation of the top of the tree as it appears to the observer: $\angle \rm B\hat{O}A = 57^\circ$ .

Let the length of segment $\rm BR$ (vertical distance between the base of the tree and the base of the hill) be $x\; \rm ft$ .

The question is asking for the length of segment $\rm AB$ . Notice that the length of this segment is $\mathrm{AB} = (x + 20)\; \rm ft$ .

The length of segment $\rm OB$ could be represented in two ways:

In right triangle $\rm \triangle OBR$ as the side adjacent to $\angle \rm B\hat{O}R = 51^\circ$ .
In right triangle $\rm \triangle OBA$ as the side adjacent to $\angle \rm B\hat{O}A = 57^\circ$ .

For example, in right triangle $\rm \triangle OBR$ , the length of the side opposite to $\angle \rm B\hat{O}R = 51^\circ$ is segment $\rm BR$ . The length of that segment is $x\; \rm ft$ .

$\begin{aligned}\tan{\left(\angle\mathrm{B\hat{O}R}\right)} = \frac{\,\rm {BR}\,}{\,\rm {OB}\,} \; \genfrac{}{}{0em}{}{\leftarrow \text{opposite}}{\leftarrow \text{adjacent}}\end{aligned}$ .

Rearrange to find an expression for the length of $\rm OB$ (in $\rm ft$ ) in terms of $x$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{BR}}{\tan{\left(\angle\mathrm{B\hat{O}R}\right)}} \\ &= \frac{x}{\tan\left(51^\circ\right)}\approx 0.810\, x\end{aligned}$ .

Similarly, in right triangle $\rm \triangle OBA$ :

$\begin{aligned}\mathrm{OB} &= \frac{\mathrm{AB}}{\tan{\left(\angle\mathrm{B\hat{O}A}\right)}} \\ &= \frac{x + 20}{\tan\left(57^\circ\right)}\approx 0.649\, (x + 20)\end{aligned}$ .