#3 the answer is 4.
The reasoning for this is because x=-1 so if it is applied where x is at you have to subtract instead of multiplying in this equation. So 2xsquared is 2-1 which is 1. Same thing for 6x (6-1) which is 5. So the problem would end up being 1-5 which equals 4.
F(x) = 1 / (x - 2)...when x = 4
f(4) = 1 / (4 - 2)
f(4) = 1/2 <==
f(x) = 1 / (x - 2)...when f(x) = 1
1 = 1 / (x - 2) ...multiply both sides by (x - 2) eliminating it on the right
1(x - 2) = 1
x - 2 = 1
x = 1 + 2
x = 3 <==
=(new-old)/old *100%
=(90-75)/75 *100%
=20%
<span> hope it helps</span>
For the fourth term r = 3
Fourth term = 6C3(x)^(6 - 3) (4y)^3 = 20x^3 (64y^3) = 1,280x^3y^3
A, C, and E.
you can check them by putting into y=mx+b form. if m is negative then as domain increases range decreases.
