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Marrrta [24]
3 years ago
10

Solve the following exponential equations. 4^x + 7(2^x) + 12 = 0

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:No value of x

Step-by-step explanation:

Given

4^x+7(2^x)+12=0

Let 2^x=y

y^2+7y+12=0

y^2+3y+4y+12=0

y(y+3)+4(y+3)=0

(y+3)(y+4)=0

y=-3,-4

2^x=-3

or 2^x=-4

so there is no value of x for which 2^x=-3 or -4

because minimum value of ^x=1

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Steps:

Step 1: Simplify both sides of the equation.

4x+3=9

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4x+3−3=9−3

4x=6

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4x /4  =  6 /4

Answer: x= 3/2

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8 0
2 years ago
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A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
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Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

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Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

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Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

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Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

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3 years ago
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By the Pythagorean theorem:

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<span>l ≤ 12
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