Question

Solve the following exponential equations. 4^x + 7(2^x) + 12 = 0

Answer 1

Answer:No value of x

Step-by-step explanation:

Given

$4^x+7(2^x)+12=0$

Let $2^x=y$

$y^2+7y+12=0$

$y^2+3y+4y+12=0$

$y(y+3)+4(y+3)=0$

$(y+3)(y+4)=0$

$y=-3,-4$

$2^x=-3$

or $2^x=-4$

so there is no value of x for which $2^x=-3 or -4$

because minimum value of $^x=1$