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Marrrta [24]
4 years ago
10

Solve the following exponential equations. 4^x + 7(2^x) + 12 = 0

Mathematics
1 answer:
andrey2020 [161]4 years ago
6 0

Answer:No value of x

Step-by-step explanation:

Given

4^x+7(2^x)+12=0

Let 2^x=y

y^2+7y+12=0

y^2+3y+4y+12=0

y(y+3)+4(y+3)=0

(y+3)(y+4)=0

y=-3,-4

2^x=-3

or 2^x=-4

so there is no value of x for which 2^x=-3 or -4

because minimum value of ^x=1

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E varies directly with The square root of C. If E=40 When C=25 find: E when C = 49 ( Please help ASAP I need to hand this in tom
DiKsa [7]

Answer:

E = 56

Step-by-step explanation:

Given that E varies directly with \sqrt{C} then the equation relating them is

E = k\sqrt{C} ← k is the constant of variation

To find k use the condition E = 40 when C = 25

k = \frac{E}{\sqrt{C} } = \frac{40}{\sqrt{25} } = \frac{40}{5} = 8, thus

E = 8\sqrt{C} ← equation of variation

When C = 49, then

E = 8 × \sqrt{49} = 8 × 7 = 56

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