408 rounded to the nearest tenth

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a2 + b2 = c2, which in this iso

abruzzese [7]

Complete Question

Because triangle XYZ is a right triangle, the side lengths must satisfy the Pythagorean theorem, a² + b² = c², which in this isosceles triangle becomes a² + a² = c². By combining like terms, 2a² = c². Which final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg?

a) substitute values for a and c into the original pythagorean theorem equation.

b) divide both sides of the equation by two, then determine the principal square root of both sides of the equation.

c) determine the principal square root of both sides of the equation.

d) divide both sides of the equation by 2.

Answer:

c) determine the principal square root of both sides of the equation.

Step-by-step explanation:

Pythagoras Theorem for a right angled triangles states that:

a²+ b²= c²

But for an Isosceles Triangle, where two sides of the triangle are equal, we have:

a²+ a² = c²

By combining like terms

2a² = c²

We square root both sides of the equation.

√2a² = √c

√2a² = c

The final step will prove that the length of the hypotenuse, c, is StartRoot 2 EndRoot times the length of each leg = √2a² = c is Option c.

4 0

3 years ago

Read 2 more answers

Plz help me I really need it

IrinaVladis [17]

Answer:

i think [after solving] that it is option B and C

Step-by-step explanation:

4 0

3 years ago

Given : If You are at least 25 years Old Then you can rent a car

KIM [24]

Answer:

Law of Syllogism

Step-by-step explanation:

4 0

3 years ago

What is the value of k in the equation 2/7(k+5/8)=2 2/7

shusha [124]

2/7 ( k+5/8) = 2 and 2/7

2/7 (k+5/8) = 16/7 |multiply by 7

2(k+5/8) = 16 |divide by 2

k+5/8 = 8 |subtract 5/8

k=8-5/8 = 7 and 3/8 = 27/8 = 7.375

7 0

3 years ago

What is the effect on the graph of the function f(x) = x^2 when f(x) is changed to f(x − 6)

olya-2409 [2.1K]

Answer:

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

Step-by-step explanation:

When we Add or subtract a positive constant, let say c, to input x, it would be a horizontal shift.

For example:

Type of change Effect on y = f(x)

$y = f(x - c)$ horizontal shift: c units to right

So

Considering the function

$f(x) = x^2$

The graph is shown below. The first figure is representing $f(x) = x^2$ .

Now, considering the function

$\:f\left(x\right)=\left(x-6\right)^2$

According to the rule, as we have discussed above, as a positive constant 6 is added to the input, so there is a horizontal shift, 6 units to the right.

The graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shown below in second figure. It is clear that the graph of $\:f\left(x-6\right)=\left(x-6\right)^2$ is shifted 6 units to the right as compare to the function $f(x) = x^2$ .

The comparison graph is also attached in 3rd figure. In the 3rd figure, the graph with vertex (0, 0) is representing $f(x) = x^2$ and $\:f\left(x\right)=\left(x-6\right)^2$ is represented as being shifted 6 units to the right as compare to the function $f(x) = x^2$ .

5 0

3 years ago