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Naily [24]
3 years ago
14

List all the forces that act on a hot air ballon when it is in the sky

Physics
2 answers:
Vikki [24]3 years ago
6 0
Down ... gravity
Up ....... buoyancy

When these are equal, then the balloon either stays at the same altitude,
or moves up or down at a constant rate.

Horizontal ... wind

When wind is not zero, the balloon accelerates in the direction of the wind.
nikdorinn [45]3 years ago
3 0
Gravity, acceleration, kinetic energy, the atmosphere
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Describe how the amount of heat released or absorbed related to specific heat capacity and amount of it? A) Amount of heat absor
Grace [21]
The correct answer is
<span>C) Amount of heat absorbed or released is doubled if quantity is doubled. If a different substance with half the specific heat capacity is used, the amount of heat absorbed or released is cut in half. 

In fact, the amount of heat released or absorbed is given by:
</span>Q=m C_s \Delta T
<span>where 
m is the mass of the substance
Cs is the specific heat capacity of the material
</span>\Delta T is the change in temperature
<span>
We can see that Q is directly proportional to both m (mass, or quantity of the substance) and Cs (specific heat capacity). So if the quantity (m) is doubled, the amount of heat (Q) is doubled as well. Similarly, if the specific heat capacity (Cs) is cut in half, the amount of heat (Q) is cut in half as well.</span>
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4 years ago
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A hydraulic machine can be used to lift extremely heavy objects. Why is the fluid in the hydraulic machine a liquid rather than
Sauron [17]
Hi,

The force that acts on hydraulic machine is heavy therefore the content must be something that cannot be compressed by that kind of force, the gas can easily be compressed while a liquid is nearly impossible to.
4 0
3 years ago
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Steve does 80 J of work to a rope threaded through a pulley and attached to a crate of anvils. The tension of the rope is 10 N a
Ivahew [28]

Answer:

The Answer is (B)

Explanation:

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3 years ago
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find an expression for a moment of inertia of a thin rod rotating about an axis passing through its center perpendicular to it's
jenyasd209 [6]

the Axis Perpendicular to the Length and Passing through the Center. Take a uniform thin rod AB whose mass is M and length is l. YY’ axis passes through the center of the rod and perpendicular to the length of the rod. We have to calculate the moment of inertia about this axis. YY’.

Suppose, small piece dx is at a distance x from the YY' axis. Hence, mass of length dx is =(

l

M

)dx The moment of inertia of small piece about the YY' axis

dl=[(

l

M

)dx]x

2

Therefore, the moment of inertia of the complete rod about the YY' axis.

b) Moment of Inertia about the axis perpendicular to the the length and passing through the Corner If I

CD

is the moment of inertia about the axis CD perpendicular to the length of a thin rod and passing through the point A then, by theorem of parallel axis;

l

CD

=l

YY

′

+Md

2

=

12

Ml

2

+M(

2

l

)

2

l

CD

=

3

Ml

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.........(2)

5 0
3 years ago
An electron moving to the right at 1.0% the speed of
AleksandrR [38]

Answer:

(a) In the direction of velocity

(b) E = - 639.84 N/C

Solution:

As per the question:

Speed of the electron, v_{e} = 0.1% c

where

c = 3\times 10^{8}\ m/s

Thus

v_{e} = 3\times 10^{6}\ m/s

Distance, x = 4.0 cm

Now,

(a) The direction of the electric field is the same as that of the velocity.

(b) The electric field strength can be calculated as:

By Kinematics eqn:

v'^{2} = v_{e}^{2} + 2ax

0 = (3\times 10^{6})^{2} + 2a\times 0.04

a = -1.125\times 10^{14}\ m/s^{2}

Electric field strength can be calculated as:

E = \frac{F}{q}

Also,

F = ma

m = mass of electron = 9.1\times 10^{- 31}\ kg

q = charge on electron = 1.6\times 10^{- 19}\ C

Thus

E = \frac{ma}{q} = \frac{9.1\times 10^{- 31}\times - 1.125\times 10^{14}}{1.6\times 10^{- 19}}

E = - 639.84 N/C

7 0
4 years ago
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