The correct answer is
<span>C) Amount of heat absorbed or released is doubled if quantity is doubled. If a different substance with half the specific heat capacity is used, the amount of heat absorbed or released is cut in half.
In fact, the amount of heat released or absorbed is given by:
</span>

<span>where
m is the mass of the substance
Cs is the specific heat capacity of the material
</span>

is the change in temperature
<span>
We can see that Q is directly proportional to both m (mass, or quantity of the substance) and Cs (specific heat capacity). So if the quantity (m) is doubled, the amount of heat (Q) is doubled as well. Similarly, if the specific heat capacity (Cs) is cut in half, the amount of heat (Q) is cut in half as well.</span>
Hi,
The force that acts on hydraulic machine is heavy therefore the content must be something that cannot be compressed by that kind of force, the gas can easily be compressed while a liquid is nearly impossible to.
the Axis Perpendicular to the Length and Passing through the Center. Take a uniform thin rod AB whose mass is M and length is l. YY’ axis passes through the center of the rod and perpendicular to the length of the rod. We have to calculate the moment of inertia about this axis. YY’.
Suppose, small piece dx is at a distance x from the YY' axis. Hence, mass of length dx is =(
l
M
)dx The moment of inertia of small piece about the YY' axis
dl=[(
l
M
)dx]x
2
Therefore, the moment of inertia of the complete rod about the YY' axis.
b) Moment of Inertia about the axis perpendicular to the the length and passing through the Corner If I
CD
is the moment of inertia about the axis CD perpendicular to the length of a thin rod and passing through the point A then, by theorem of parallel axis;
l
CD
=l
YY
′
+Md
2
=
12
Ml
2
+M(
2
l
)
2
l
CD
=
3
Ml
2
.........(2)
Answer:
(a) In the direction of velocity
(b) E = - 639.84 N/C
Solution:
As per the question:
Speed of the electron,
= 0.1% c
where
c = 
Thus

Distance, x = 4.0 cm
Now,
(a) The direction of the electric field is the same as that of the velocity.
(b) The electric field strength can be calculated as:
By Kinematics eqn:


Electric field strength can be calculated as:

Also,
F = ma
m = mass of electron = 
q = charge on electron =
Thus

E = - 639.84 N/C