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KATRIN_1 [288]
3 years ago
8

In general, what happens to temperature as depth below earths surface increases

Physics
1 answer:
lesantik [10]3 years ago
8 0
Temperature increases as depth increases.
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An unmanned spacecraft leaves for Venus. Which statements about the spacecrafts journey are true?
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Explanation:

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The concentration of a solution that contains 70g of H2SO4 in 0,28 dm³ of solution is?​
Simora [160]

Taking into account the definition of molarity, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \frac{moles}{L}.

<h3>Definition of molarity</h3>

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

Molarity=\frac{number of moles}{volume}

Molarity is expressed in units \frac{moles}{L}.

<h3>This case</h3>

In this case, you have:

  • number of moles= 70 g×\frac{1 mole}{98 g}= 0.7143 moles, where 98 g/mole os the molar mass of H₂SO₄
  • volume= 0.28 dm³= 0.28 L (being 1 dm³= 1 L)

Replacing in the definition of molarity:

Molarity=\frac{0.7143 moles}{0.28 L}

Solving:

<u><em>Molarity= 2.5510 </em></u>\frac{moles}{L}

Finally, the concentration of a solution that contains 70 g of H₂SO₄ in 0,28 dm³ of solution is 2.5510 \frac{moles}{L}.

Learn more about molarity:

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4 0
2 years ago
Prove the correctness of this equation s=vt + 1/2at ​
Kaylis [27]

Answer:

The formula is dimensionally correct.

Explanation:

Given

s = ut + \frac{1}{2}at^2

Required

Prove its correctness

Write out the dimension of each:

s = M^0LT^0 --- displacement

ut = M^0LT^{-1} *  T --- velocity * time

\frac{1}{2}at^2 = M^0LT^{-2} * T^2 --- acceleration * square of time

The expression becomes:

s = ut + \frac{1}{2}at^2

M^0LT^0 = M^0LT^{-1} *  T + M^0LT^{-2} * T^2

Apply law of indices

M^0LT^0 = M^0LT^{-1+1} + M^0LT^{-2+2}

M^0LT^0 = M^0LT^{0} + M^0LT^{0}

M^0LT^0 = M^0LT^{0}

Both sides of the equation are equal

5 0
3 years ago
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