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Anastasy [175]
3 years ago
10

a student 600 ml cup of cocoa gets cold. It was only 25°C. He put it in the microwave. How many calories must transfer to the co

coa to bring it up to 70°C
Chemistry
1 answer:
EleoNora [17]3 years ago
3 0

To get the answer, you must know first the formula for heat.

Heat = mass X specific heat X change in temp 

We know that the mass is 600

Specific heat is 1

And the change in temperature is 70 – 25 which is 45.

Now plugging in those values:

 

Heat = 600 x 1 x 45 = 27,000 calories


Note: calorie is a unit of heat

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Number of moles in 31.99g O2 <br> And 176.8g NaCl
sergey [27]

#O_2

\\ \sf\longmapsto No\:of\;moles=\dfrac{Given\:mass}{Molar\:mass}

\\ \sf\longmapsto No\:of\:moles=\dfrac{31.99}{32}

\\ \sf\longmapsto No\:of\:moles\approx 1

#NaCl

\\ \sf\longmapsto No\:of\:moles=\dfrac{176.8}{58.5}

\\ \sf\longmapsto No\;of\:moles=3mol

8 0
2 years ago
How to do q solution, qrxn, moles of Mg , and delta Hrxn?
Helga [31]

Answer:

<em> 14, 508J/K</em>

ΔHrxn =q/n

where q = heat absorbed and n = moles

Explanation:

<em>m = mass of substance (g) = 0.1184g</em>

1 mole of Mg - 24g

<em>n</em> moles - 0.1184g

<em>n = 0.0049 moles.</em>

Also, q = m × c × ΔT

<em> Heat Capacity, C of MgCl2 = 71.09 J/(mol K)</em>

<em>∴ specific heat c of MgCL2 = 71.09/0.0049 (from the formula c = C/n)</em>

<em>= 14, 508 J/K/kg</em>

ΔT=  (final - initial) temp = 38.3 - 27.2

= 11.1 °C.

mass of MgCl2 = 95.211 × 0.1184 = 11.27

⇒ q = 11.27g × 11.1 °C × <em>14, 508 j/K/kg </em>

<em>= 1,7117.7472 J °C-1 g-1</em>

<em />

<em>∴ ΔHrxn = q/n</em>

<em>=1,7117.7472  ÷ 0.1184 </em>

<em>= 14, 508J/K</em>

6 0
4 years ago
How do I do this? It's in Chemistry, and it has to do with Single Replacement
Setler [38]
Is there any more to the picture?
4 0
3 years ago
An aqueous solution at 25.0°C contains [H+] = 0.075 M. What is the pH of the solution?
olasank [31]

Answer:

1.131

Explanation:

pH=-logH^+

H^+=0.074

pH=-log 0.074

pH=1.131

7 0
3 years ago
PLEASE HELP!!!!
bija089 [108]

Answer:

Molar mass = 18.12 g/0.777 moles = 23.3 g/mole

i hope this helps

Explanation:

4 0
3 years ago
Read 2 more answers
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