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vodomira [7]
3 years ago
12

What element has the following electron configuration 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f14 6

d8?
Chemistry
1 answer:
musickatia [10]3 years ago
8 0

Answer:

Explanation:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ 5s² 4d¹⁰ 5p⁶ 6s² 4f¹⁴ 5d¹⁰ 6p⁶ 7s² 5f¹⁴ 6d⁸

The element is Darmstadtium . It is a d block element . Its symbol is Ds . Its atomic no is 110 .

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If an atom of Bromine (Br) becomes an ion, which of the following does it most likely form?
lawyer [7]

Answer:

An atom of Bromine (Br) forms an ion and becomes Br⁻

Explanation:

  • Atoms of elements gain or lose electron(s) to attain a stable configuration and form ions.
  • When an atom gains electron(s) it forms a negatively charged ion called an anion.
  • For example, Bromine is a halogen and its atom requires to gain one electron to attain stability and form a bromine ion (Br⁻).
  • When an atom loses electron(s) it forms a positively charged ion called a cation.
  • For instance, atoms of calcium(Ca) requires to lose two electrons to attain stability and form calcium ion (Ca²⁺).

5 0
3 years ago
Gravitational force acts on two objects with which of the following?
ikadub [295]
The correct answer is A.

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5 0
3 years ago
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The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget?
Bezzdna [24]
Density = mass / volume
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8 0
3 years ago
How much energy (in Joules) would it take to warm 3.11 grams of gold by 7.7 oC
Reptile [31]

Answer:

It would take 3.11 J to warm 3.11 grams of gold

Explanation:

Step 1: Data given

Mass of gold = 3.11 grams

Temperature rise = 7.7 °C

Specific heat capacity of gold = 0.130 J/g°C

Step 2: Calculate the amount of energy

Q = m*c*ΔT

⇒ Q = the energy required (in Joules) = TO BE DETERMINED

⇒ m = the mass of gold = 3.11 grams

⇒ c = the specific heat of gold = 0.130 J/g°C

⇒ ΔT = The temperature rise = 7.7 °C

Q = 3.11 g * 0.130 J/g°C * 7.7 °C

Q = 3.11 J

It would take 3.11 J to warm 3.11 grams of gold

4 0
3 years ago
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Nesterboy [21]
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3 0
3 years ago
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