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Sonja [21]
3 years ago
14

How many atoms of mercury are present in 3.4 cubic centimeters of liquid mercury? the density of mercury is 13.55 g/cc?

Chemistry
1 answer:
maks197457 [2]3 years ago
8 0

Answer:

             1.37 × 10²³ Atoms of Mercury  

Solution:

Step 1: Calculate Mass of Mercury using following formula,

                               Density  =  Mass ÷ Volume

Solving for Mass,

                               Mass  =  Density × Volume

Putting values,

                               Mass  =  13.55 g.cm⁻³ × 3.4 cm³                ∴ 1 cm³ = 1 cc

                               Mass  =  46.07 g

Step 2: Calculating number of Moles using following formula;

                               Moles  =  Mass ÷ M.mass

Putting values,

                               Moles  =  46.07 g ÷ 200.59 g.mol⁻¹

                               Moles  =  0.229 mol

Step 3: Calculating Number of Atoms using following formula;

                               Number of atoms  =  Moles × 6.022 ×10²³

Putting value of moles,

                               Number of Atoms  =  0.229 mol × 6.022 × 10²³

                              Number of Atoms  =  1.37 × 10²³ Atoms of Hg

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itrogen forms a number of different compounds with oxygen, depending upon the experimental conditions. This type of observation
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Answer:

the Law of multiple proportions

Explanation:

The law of multiple proportions states that, if two elements A and B combine to form more than one chemical compound, then the various masses of one of the elements A, which combines with a fixed mass of the element B are in simple multiple ratio.

This is demonstrated in the formation of nitrogen compounds such as NO and N2O when nitrogen combines with oxygen. This ratio is always constant.

5 0
3 years ago
How many atoms are in 1.0 formula units of magnesium acetate?
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Answer:

15

Explanation:

Magnesium Acetate Mg(C2H3O2)2

Number of atoms:

Carbon = 4

Hydrogen = 6

Magnesium = 1

Oxygen = 4

Total = 15

7 0
3 years ago
When a 3.00 grams sample of a compound containing only c, h, and o was completely burned, 1.17 grams of h2o and 2.87 grams of co
SVEN [57.7K]

Answer:- CH_2O_2

Solution:- From given masses of carbon dioxide and water we could calculate the moles that helps to calculate the moles of C and H.

Molar mass of carbon dioxide = 44 gram per mol

molar mass of water = 18.02 gram per mol

From given info, combustion of compound gives 1.17 grams of water and 2.87 grams of carbon dioxide. Let's calculate the moles of these:

1.17gH_2O(\frac{1mol}{18.02g})

= 0.0649molH_2O

Similarly, 2.87gCO_2(\frac{1mol}{44g})

= 0.0652molCO_2

One mol of water has two moles of H. So, the moles of H would be two times the moles of water as calculated above.

So, moles of H = 2* 0.0649 = 0.1298 mol

One mol of carbon dioxide contains one mol of C. So, the moles of C would be equal to the moles of carbon dioxide calculated above.

moles of C = 0.0652 mol

Let's convert the moles of H and C to grams so that we could calculate the amount of oxygen present in the sample as:

grams of H in sample = 1.008 x 0.1298 = 0.1308 g

grams of C in sample = 12*0.0652 = 0.7824 g

If we subtract the sum of the masses of C and H from sample mass then it would give as the mass of oxygen since the sample has only C, H and O.

mass of O in sample = 3.00g - (0.1308 g + 0.7824 g)

= 3.00 g - 0.9132 g

= 2.0868 g

Let's convert these grams of oxygen to moles on dividing by it's atomic mass as:

2.0868gO(\frac{1mol}{15.999g})

= 0.130 mol O

Now, we have the moles of all the three atoms and we know that an empirical formula is the simplest whole number ratio of the moles of atoms. So, let's calculate the ratio. For this, we divide the moles of each by the least one of them.Looking at the moles, the least value is for carbon. So, let's divide the moles of each by the moles of C as:

C = \frac{0.0652}{0.0652}  = 1

H = \frac{0.1298}{0.0652}  = 2

O = \frac{0.130}{0.0652}  = 2

The ratio of C, H and O is 1:2:2. So, the simplest formula of the compound is CH_2O_2 .



3 0
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Si agrega un ácido a una base, ¿qué pasará?
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Answer:

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Explanation:

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Answer:

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