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Semmy [17]
3 years ago
15

For H2O, determine the specified property at the indicated state.

Engineering
1 answer:
zheka24 [161]3 years ago
7 0

Answer:

3.613 bar

1.0290 m3/kg

0.038378 m3/kg

1.363 m3/kg

0.012166 m3/kg

0.002083 m3/kg

0.001177 m3/kg

Explanation:

part a

Table A-3: vf = 1.0435 x 10-3 m 3/kg , vg = 1.673 m 3 /kg. Since vf < v < vg, the state is in the two phase liquid-vapor region, as shown.

From Table A-3, the pressure is the saturation is pressure at 140 C: p = 3.613 bar.

Answer: p = 3.613 bar

part b

The pressure is higher than the critical  pressure, as shown on the diagram. Hence, the  state is in the compressed liquid region.

From Table A-5: v = 1.0290 m3 /kg.

Answer: v = 1.0290 m3 /kg

part c

Since the temperature is higher than Tsat at 100  bar, the state is super-heated vapor. T sat = 311.1 C

Interpolating in Table A-4, we get

v = 0.038378 m3/kg

Answer: v = 0.038378 m3/kg

part d

vx = vf + x(vg – vf)

v = 1.0291 x 10-3 + (0.4)(3.407 - 1.0291 x 10-3 )

v = 1.363 m3/kg

Answer: v = 1.363 m3/kg

a ) T = 440 C , p = 20 MPa

Tsat(@20 MPa) = 365.75 C

T > Tsat(@20 MPa) hence, super-heated steam

Interpolate the results

v = 0.012166 m3/kg

Answer: v = 0.012166 m3/kg

b) T = 160 C , p= 20 MPa

Tsat(@20 MPa) = 365.75 C

T < Tsat(@20 MPa) hence, compressed liquid region

v = 0.002038 m3/kg

Answer: v = 0.002038 m3/kg

c) T = 40 C , p = 2 MPa

Tsat(@2 MPa) = 212.38 C

T < Tsat(@2 MPa) hence, compressed liquid region

v = 0.001177 m3/kg

Answer: v = 0.001177 m3/kg

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Determine the carburizing time necessary to achieve a carbon concentration of 0.30 wt.% at a position of 4 mm into an iron-carbo
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The carburizing time necessary to achieve a carbon concentration is 31.35 hours

<h3>How to find the Carburizing Time?</h3>

To determine the carburizing time necessary to achieve the given carbon concentration, we will use the equation:

(Cs - Cx)/(Cs - C0) = ERF(x/2√Dt)

where;

Cs is Concentration of carbon at surface = 0.90

Cx is Concentration of carbon at distance x = 0.30

Distance x = 4 mm = 0.004 m

C0 is Initial concentration of carbon = 0.10

ERF() = Error function at the given value

D = Diffusion of Carbon into steel

t = Time necessary to achieve given carbon concentration ,

Thus, plugging in the relevant values gives;

(Cs - Cx)/(Cs - C0) = (0.9 - 0.3)/(0.9 - 0.1)

= 0.6/0.8 = 0.75

now, ERF(z) = 0.75 and as such using ERF table, we can say that;

Z = 0.814. Thus;

(x/2√Dt) = 0.81

Using the table of diffusion data, we have;

At a temperature of  (1100°C) or 1373 K, we have;

D = 5.35 × 10⁻¹¹ m²/sec.

Calculating the carbonizing time by using the equation z = (x/2√Dt);

where;

t is carbonizing time

Thus;

0.814 = (0.004/(2 × √5.35 × 10⁻¹¹ × √t))

0.814 = 0.004 /(1.4628 × 10⁻⁵ × √t)

0.814 × 1.4628 × 10⁻⁵ × √t = 0.004

1.19072 × 10⁻⁵ × √t = 0.004  

√t = 0.004/(1.19072 × 10⁻⁵)

√t = 335.93

t = 112848.96 seconds

Converting to hours gives;

t = 112848.96/3600

t = 31.35 hours

Therefore, the carburizing time necessary to achieve a carbon concentration is 31.35 hours

Read more about Carburizing Time at; brainly.com/question/13031810

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